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Alchen [17]
3 years ago
14

Find the equation of the circle that has a diameter with endpoints located at (-5,-3) and (-11,-3)

Mathematics
1 answer:
zvonat [6]3 years ago
4 0
x^{2} + y^{2} = r^{2}
Radius;
\sqrt{(-5--11)^{2} + (-3--3)^{2}
x^{2} + r^{2} =36

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What does 3-3x6+2 equal?
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Okay I don't understand how do I do this. It say :
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PLEASE ANSWER CORRECTLY, I WILL GIVE BRAINLIEST <3 THANKS IN ADVANCE!
guajiro [1.7K]

Answer:

1 : 15

2: 12

3: 52

4: 27.3

Step-by-step explanation:

For #1:

if line m and n are perpendicular then they will create right angles

Right angles have a measure of 90 degrees

That being said we can find the measure of the missing angle by subtracting the measure of the known angle (75) from 90

so k = 90 - 75

90 - 75 = 15

Hence k = 15.

For #3 ( very similar to #1, only difference is the values of the angles )

so R = 90 - 38

90 - 38 = 52

Hence, R = 52

For #2 and #4

Complementary angles have a sum of 90°

So like the previous questions we can find the measure of the missing angle by subtract the measure of the given angle from 90

∠V = 90 - 78

90 - 78 = 12

Hence ∠V = 12

∠Y = 90 - 62.7

90 - 62.7 = 27.3

Hence ∠Y = 27.3

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2 years ago
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Answer:

y=3/4x+(-2) aka the first blank is 3/4 the second blank is -2

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6 0
3 years ago
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