3 years ago

Find the equation of the circle that has a diameter with endpoints located at (-5,-3) and (-11,-3)

Mathematics

1 answer:

zvonat [6]3 years ago

4 0

$x^{2} + y^{2} = r^{2}$
Radius;
$\sqrt{(-5--11)^{2} + (-3--3)^{2}$
$x^{2} + r^{2} =36$

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Hello

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...........| 0...| 1..| 2..| 3..| 4..| write numbers
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...........| 0...|1/2|√2/2|√3/2|1| divide by 2
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Answer:

Step-by-step explanation:

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Read 2 more answers