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Alchen [17]
2 years ago
14

Find the equation of the circle that has a diameter with endpoints located at (-5,-3) and (-11,-3)

Mathematics
1 answer:
zvonat [6]2 years ago
4 0
x^{2} + y^{2} = r^{2}
Radius;
\sqrt{(-5--11)^{2} + (-3--3)^{2}
x^{2} + r^{2} =36

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Answer:

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Step-by-step explanation:

Let

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The perimeter =14 in
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