2 years ago

Find the equation of the circle that has a diameter with endpoints located at (-5,-3) and (-11,-3)

Mathematics

1 answer:

zvonat [6]2 years ago

4 0

$x^{2} + y^{2} = r^{2}$
Radius;
$\sqrt{(-5--11)^{2} + (-3--3)^{2}$
$x^{2} + r^{2} =36$

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