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kumpel [21]
3 years ago
14

Determine whether it’s always, never, or sometimes true. I put never true. Is that right?

Mathematics
1 answer:
DiKsa [7]3 years ago
4 0

Answer:

yes the answer is never true

Step-by-step explanation:

as the correct answer is

\sqrt{2x}

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907 rounded to the nearest ten is ?
aniked [119]

Answer:910

Step-by-step explanation: it rounds up because if the last number is more than 5 you round up

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2 years ago
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Which of the following is not a step in the conversion of 1.3 dam3 to L?
aivan3 [116]
<span>(10^-3L/1mL)^3 is the correct answer.</span>
4 0
3 years ago
5. There are 8 sections of seats in an auditorium. Each section contains at least 150 seats but not more than 200 seats. Which o
zaharov [31]

Answer:

1300

Step-by-step explanation:

Given that :

Number of sections = 8

Number of seats per section, x ;

150 ≤ x ≤ 200

The possible Number of seats in the auditorium :

Number of seats per section * number of sections

150 * 8 ≤ x ≤ 200 * 8

1200 ≤ x ≤ 1600

The possible Number of seats will lie within 1200 and 1600

From the options, only 1300 lie within this range

4 0
2 years ago
Explain why Rolle's Theorem does not apply to the function even though there exist a and b such that f(a)
Anna35 [415]

Rolle's Theorem does not apply to the function because there are points on the interval (a,b) where f is not differentiable.

Given the function is f(x)=\sqrt{(2-x^{\frac{2}{3}})^{3}}  and the Rolle's Theorem does not apply to the function.

Rolle's theorem is used to determine if a function is continuous and also differentiable.

The condition for Rolle's theorem to be true as:

  • f(a)=f(b)
  • f(x) must be continuous in [a,b].
  • f(x) must be differentiable in (a,b).

To apply the Rolle’s Theorem we need to have function that is differentiable on the given open interval.

If we look closely at the given function we can see that the first derivative of the given function is:

\begin{aligned}f(x)&=\sqrt{(2-x^{\frac{2}{3}})^3}\\ f(x)&=(2-x^{\frac{2}{3}})^{\frac{3}{2}}\\ f'(x)&=\frac{3}{2}(2-x^{\frac{2}{3}})^{\frac{1}{2}}\cdot \frac{2}{3}\cdot (-x)^{\frac{1}{3}}\\ f'(x)&=\frac{-\sqrt{2-x^{\frac{2}{3}}}}{\sqrt[3]{x}}\end

From this point of view we can see that the given function is not defined for x=0.

Hence, all the assumptions are not satisfied we can reach a conclusion that we cannot apply the Rolle's Theorem.

Learn more about Rolle's Theorem from here brainly.com/question/12279222

#SPJ4

8 0
2 years ago
Math help please show work I will make brainlist if correct thanks
emmasim [6.3K]

Step-by-step explanation:

number 1 is 68 degrees Fahrenheit and number 2 is 98.6=37 degrees Celsius and 102 fahrenheit is higher than the normal

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