Question

Plz help, will mark brainliest!

Answer 1

Answer:

the answer is "B" (thank me later) ;))

Answer 2

Answer:

Given:- $f(x)=\frac{x-3}{x+2}$

Solution:- $\left(-\infty \:,\:-2\right)\cup \left(-2,\:\infty \:\right)$

So, Answer:- $All \: real\: value \: of x\: such \; that \: \neq -2$

OAmalOHopeO