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rodikova [14]
3 years ago
9

I will give brainliest to whoever can answer this question. It’s due in 40 min Please help me )):

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
5 0

Given:

m\angle L=m\angle Z=70^\circ

m\angle N=m\angle Y=90^\circ

To find:

The value of m\angle 1.

Solution:

In triangle XYZ,

m\angle Y=m\angle N=90^\circ        (Given)

m\angle Z=m\angle L=70^\circ         (Given)

m\angle X+m\angle Y+m\angle Z=180^\circ        [Angle sum property]

m\angle 1+90^\circ+70^\circ=180^\circ

m\angle 1+160^\circ=180^\circ

m\angle 1=180^\circ-160^\circ

m\angle 1=20^\circ

Therefore, the m\angle 1 is 20°.

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Art [367]

Answer:

3.6 pounds

Step-by-step explanation:

If 1 bottle weighs 3/5 pounds

the 6 bottles will weigh 6 x 3/5

= 18/5

ratio method :

1:3/5

6:x

since the ratios are direct we can cross multiply

18/5 = 1x

so the 6 bottles weigh 18/5 pounds or 3.6 pounds

5 0
3 years ago
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What are the solutions of the system? {y=2x+6y=x2+5x+6 ​(−3, 0)​ and (−2, 0) (0, −3) and (6, 0) (−3, 0) and (0, 6) ​(0, 6)​ and
SSSSS [86.1K]
<span>(−3, 0) and (0, 6)

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3 years ago
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Attached as picture. Please read fully
Troyanec [42]

a. The velocity t = v = Ce_{n} (\frac{mo}{mo - kt} ) - gt

b. v60 = 7164

<h3>How to solve for the velocity</h3>

mdv/dt = ck - mg

dv/dt = ck/m - mg/m

= ck/m - g

dv = (\frac{ck}{Mo-Kt} -g)dv

Integrate the two sides of the equation to get

v -\frac{ck}{k} e_{n} (Mo- kt)-gt+c

v = Ce_{n} (\frac{mo}{mo - kt} ) - gt

b. fuel accounts for 55% of the mass

So final mass after fuel is burned out is = 0.45

c=2500

g=9.8

t=60

v = -2500ln0.45 - 9.8 x 60

= 7752 - 588

= 7164

<h3>Complete question</h3>

A rocket, fired from rest at time t = 0, has an initial mass of m0 (including its fuel). Assuming that the fuel is consumed at a constant rate k, the mass m of the rocket, while fuel is being burned, will be given by m0 - kt. It can be shown that if air resistance is neglected and the fuel gases are expelled at a constant speed c relative to the rocket, then the velocity of the rocket will satisfy the equation where g is the acceleration due to gravity.

dv dt m =ck - mg

(a) Find v(t) keeping in mind that the mass m is a function of t.

v(t) =

m/sec

(b) Suppose that the fuel accounts for 55% of the initial mass of the rocket and that all of the fuel is consumed at 60 s. Find the velocity of the rocket in meters per second at the instant the fuel is exhausted. [Note: Take g = 9.8 m/s² and c = 2500 m/s.]

v(60) =

m/sec [Round to nearest whole number]

Raed more on velocity here

brainly.com/question/25749514

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8 0
1 year ago
(x + 2)2 + (y - 3)2 = 4
Lostsunrise [7]
Answer: x=3

Step by Step:
(x+2)2+(y-3)2=4
2x+4+(0-3)x2=4
2x+4-3x2=4
2x+4-6=0
2x=6
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8 0
3 years ago
Sam is trying to make 12 packs of rice. She packed 2 1/2 kg of rice in each of the first 4 packs &amp; 2 3/4 kg of rice in each
Lina20 [59]

Answer:

32 kg

Step-by-step explanation:

1. Convert the fractions to decimals:

2 1/2 = 2.5

2 3/4 = 2.75

2. Set up the equation to show 4 packs of 2.5 kg and 8 packs of 2.75 kg:

4*(2.5) + 8*(2.75)

3. Solve the equation using PEMDAS:

4(2.5) + 8(2.75)

10 + 8(2.75)

10 + 22

32

8 0
3 years ago
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