To do this, you have to plug each x value into the rule.
1.y = 15 - 3×2
y = 15 - 6
y = 9
So the first y value would be 9.
2.y = 15 - 3×3
y = 15 - 9
y = 6
3. y = 15 - 3×4
y = 15-12
y = 3
4. y = 15 - 3×5
y = 15-15
y = 0
Hope this helps!
If you have multiple equations with multiple variables, you can either do clever substitutions, or turn it into a matrix on which you can perform linear combinations or multiplications (Gauss elimination)
1 1 1 1
2 1 -1 8
1 -1 1 -5
(note how the above 3 rows represent the 3 equations, just got rid of the variables, plus sign and equals sign)
subtract row1 from row3, that eliminates x and z from row 3.
1 1 1 1
2 1 -1 8
0 -2 0 -6
divide row3 by -2, that will give y a factor of 1
1 1 1 1
2 1 -1 8
0 1 0 3
The last row now says y=3
Answer: 35000/20000=1.75 pound
Step-by-step explanation:
Answer:
the answer is 52.
Step-by-step explanation:
You have to do [(6+6+2)*(3)] + [(2)*(5)] to get your answer.
(6+6+2)=14
14*3=42
2*5=10
10+42=52
Answer:
61
Step-by-step explanation:
aₙ = a₁ + (n - 1)d
aₙ = 4 + (20 - 1)3
aₙ = 4 + (19)3
aₙ = 4 + 57
aₙ = 61