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Scilla [17]
3 years ago
7

31 is 20% of what number

Mathematics
2 answers:
andrezito [222]3 years ago
7 0
31 is 20% of 155 :3
zloy xaker [14]3 years ago
6 0
155 because that 20% is 1/5 of a number add 31 5 times or 31 times which is 155
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GIVEAWAY!!! <br> 50PTS + BRAINLIEST <br><br> 4(2x)−8x+4
blagie [28]

Answer:

4(2x) - 8x + 4

4 × 2x = 8x

8x - 8x + 4

= 4

8 0
2 years ago
alaina owes her mom $15 and her friend $27. then she babysat and earned $35. how much more money does alaina need to earn in ord
tino4ka555 [31]

35 - 27 = 8

15 - 8 = 7

She just payed off her best friend and has $8 left.

So she needs to earn $7 more to pay off the $15 she owes her mom

4 0
3 years ago
What word describes the equal shares of the shape
nexus9112 [7]
The word that describes it is congruent
7 0
3 years ago
Select the correct answer from each drop-down menu.
serious [3.7K]

Answer:

Center: (4,8)

Radius: 2.5

Equation: (x-4)^2+(y-8)^2=6.25

Step-by-step explanation:

It was given that; the endpoints of the longest chord on a circle are (4, 5.5) and (4, 10.5).

Note that the longest chord is the diameter;

The midpoint of the ends of the diameter gives us the center;

Use the midpoint formula;

(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )

The center is at; (\frac{4+4)}{2} ,\frac{5.5+10.5}{2}=(4,8)

To find the radius, use the distance formula to find the distance from the center to one of the endpoints.

The distance formula is;

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

r=\sqrt{(4-4)^2+(10.5-8)^2}

r=\sqrt{0^2+(2.5)^2}

r=\sqrt{0^2+(2.5)^2}=2.5

The equation of the circle in standard form is given by;

(x-h)^2+(y-k)^2=r^2

We substitute the center and the radius into the formula to get;

(x-4)^2+(y-8)^2=2.5^2

(x-4)^2+(y-8)^2=6.25

6 0
3 years ago
Simplify the expression using trigonometric identities: sec (–θ) – cos θ.
ololo11 [35]

Answer:

sin θ . tan θ

Step-by-step explanation:

Note : -

sec ( - θ ) = sec θ

Formula / Identity : -

sec θ = 1 / cos θ

sec ( - θ ) - cos θ

= [ 1 / cos θ ] - cos θ

{ LCM = cos θ }

= [ 1 / cos θ ] - [ cos²θ / cos θ ]

= [ 1 - cos²θ ] / cos θ

{ 1 - cos²θ = sin²θ }

= sin²θ / cos θ

{ sin²θ = sin θ . sin θ }

= sin θ . sin θ / cos θ

{ sin θ / cos θ = tan θ }

= sin θ . tan θ

Hence, simplified.

4 0
2 years ago
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