Answer:
The first five terms of the given sequence
3, 6, 11, 18, 27
Step-by-step explanation:
It is given that,
an=n² +2
<u>To find the first five terms</u>
a₁ = 1² + 2 = 1 + 2 = 3
a₂ = 2² + 2 = 4 + 2 = 6
a₃ = 3² + 2 = 9 + 2 = 11
a₄ = 4² + 2 = 16 + 8 = 18
a₅ = 5² + 2 = 25 + 2 = 27
Therefore the first five terms of the given sequence
3, 6, 11, 18, 27
Answer:
x = 11, y = 8
Step-by-step explanation:
ΔABC and ΔFDE are congruent by the postulate SSS
Equate the congruent sides in the 2 triangles
BC = ED, that is
x + 3 = 14 ( subtract 3 from both sides )
x = 11
-------------------------------------
DF = AB, that is
x - y = 3 ← substitute x = 11
11 - y = 3 ( subtract 11 from both sides )
- y = 3 - 11 = - 8 ( multiply both sides by - 1 )
y = 8
Answer:
just 4 words only
Step-by-step explanation:
in order to maintain the rules
I am pretty sure that it's
A. 1
