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3 years ago

Write the number 4, 207 in expanded form.

Mathematics

1 answer:

Arisa [49]3 years ago

8 0

Answer:

(4.1000)+ (2.100) + (7.10)

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How do you simplify 1/5 x 22

svetlana [45]

Answer:

The person above is correct

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What is the range of the following function

Shtirlitz [24]

The answer: -5 ≤ y ≤ 6

The range is all the possible output or y values of the function.

Our first point is at (1, 6) and our second point is at (-4, -5)

That means our y values are 6 and -5. Let's set up a compound inequality to represent our function.

-5 ≤ y ≤ 6. This means that x is greater than or equal to -5 and less than or equal to 6.

7 0

3 years ago

What is the solution set for the inequality 2x-3> 5x+6?

prisoha [69]

$3x < - 9 \\ x < - 3$

4 0

3 years ago

5n+-3n=-18 solve for n

Hoochie [10]

Answer:

$\: \: \: \: \: \: \: \: 5n + ( - 3n) = - 18 \\ = > 5n - 3n = - 18 \\ = > 2n = - 18 \\ = > n = \frac{ - 18}{2} \\ = > n = - 9$

8 0

3 years ago

A well known pharmaceutical manufacturer is manufacturing a newly developed vaccine, and is concerned about variability in the i

Lana71 [14]

Answer:

The null hypothesis is $H_o : \ \sigma^2 = 1.9$

The alternative hypothesis is $H_a : \ \sigma^2 \ne 1.9$

$X^2 = 13.74$

The decision rule is

Reject the null hypothesis

The conclusion is

There is no sufficient evidence to conclude that the variance of the immune response is equal to 1.9.

Step-by-step explanation:

From the question we are are told that

The variance is $\sigma ^2 = 1.9$

The sample size is n = 30

The sample variance is $s^2 = 0.9$

The level of significance is $\alpha = 0.05$

The null hypothesis is $H_o : \ \sigma^2 = 1.9$

The alternative hypothesis is $H_a : \ \sigma^2 \ne 1.9$

Generally the test statistics is mathematically represented as

$X^2 = \frac{ (n- 1 ) * s^2 }{ \sigma^2 }$

=> $X^2 = \frac{ (30 - 1 ) * 0.9 }{1.9 }$

=> $X^2 = 13.74$

Generally from the degree of freedom is mathematically represented as

$df = n- 1$

=> $df = 30 - 1$

=> $df = 29$

Generally from the chi distribution table the critical value of $\frac{\alpha}{2} \ and \ 1 - \frac{ \alpha }{2}$ at a degree of freedom of $df = 29$ is

$X^2 _{ \frac{\alpha }{2} , df } = X^2 _{ \frac{0.05 }{2} , 29 } = 45.7$

=> $X^2 _{ 1 - \frac{\alpha }{2} , df } = X^2 _{1 - \frac{0.05 }{2} , 29 } = 16.0 5$

Gnerally from the values obtained we see that

$X^2 < X^2 _{ 1 - \frac{\alpha }{2} , df }$ hence

The decision rule is

Reject the null hypothesis

The conclusion is

There is no sufficient evidence to conclude that the variance of the immune response is equal to 1.9.

6 0

3 years ago