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Cerrena [4.2K]
4 years ago
11

What is the range of the following function

Mathematics
1 answer:
Shtirlitz [24]4 years ago
7 0

The answer: -5 ≤ y ≤ 6

The range is all the possible output or y values of the function.

Our first point is at (1, 6) and our second point is at (-4, -5)

That means our y values are 6 and -5. Let's set up a compound inequality to represent our function.

-5 ≤ y ≤ 6. This means that x is greater than or equal to -5 and less than or equal to 6.

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What is the constant proportionality of (2, 0) (4, 2) (6, 4) (8, 6)
Marysya12 [62]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
Find the value of the trigonometric ratio. Make sure to simplify the fraction if needed. plss help
Natalija [7]

Answer:

3/5

Step-by-step explanation:

sinA = opp/hyp

= 21/35

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8 0
3 years ago
For each set of side listed determine if the given triangle is right triangle, obtuse or acute
nasty-shy [4]
Right triangle. You can tell because of the tiny square in the corner. This indicated that angle is equal to 90°. Any triangle that has 90° is a right triangle
3 0
3 years ago
What is the value of f(-2) if f(x) = - 3x2 + 4x - 1
pashok25 [27]

Given the function below:

\large{f(x) =  - 3 {x}^{2}  + 4x - 1}

To find f(-2), we substitute x = -2 in the equation. Since f(-2) means the value of f(x) at x = -2.

\large{f( - 2) =  - 3 {( - 2)}^{2}  + 4( - 2) - 1}

Replace x-term to -2 and evaluate.

\large{f( - 2) =  - 3(4) - 8 - 1} \\  \large{f( - 2) =  - 12 -  8 - 1 \longrightarrow f( - 2) =  - 21}

Answer

  • f(-2) = -21

Let me know if you have any doubts!

4 0
3 years ago
Which function has two x-intercepts, one at (0, 0) and one at (4, 0)? f(x) = x(x − 4) f(x) = x(x + 4) f(x) = (x − 4)(x − 4) f(x)
Fofino [41]

If you want a polynomial to have the x-intercepts of your choice, you simply have to build a polynomial by multiplying pieces like (x-x_k) where x_k is the x-intercept you want.

So, if you want x-intercepts 0 and 4, you have to build the polynomial

(x-0)(x-4) = x(x-4)

5 0
3 years ago
Read 2 more answers
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