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Ganezh [65]
3 years ago
15

PLEASE HELPPPPP HERTHRETHH

Mathematics
1 answer:
Mkey [24]3 years ago
8 0

Answer:

true.

Step-by-step explanation:

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At a sale, dresses were sold for $90 each. This price was 75% of a
gulaghasi [49]

Answer:

A dress originally costs $120

Step-by-step explanation:

To find the original cost of the dress, we will follow the steps below;

let x represent the original cost of the dress

75% of x  = $90

\frac{75}{100}  ×    x   = $90

\frac{75X}{100}  =   $90

MULTIPLY both-side of the equation by 100

\frac{75X}{100} × 100 =   $90×100

At the right-hand side of the equation, 100 will cancel out 100, leaving us with just 75x

75x = $9000

DIVIDE both-side of the equation by 75

75x/75 = $9000/75

At the left-hand side of the equation 75 will cancel-out 75 leaving us with just x

x=  $9000/75

x = $120

A dress originally costs $120

3 0
3 years ago
Please help me with imaginary numbers.
uysha [10]

Answer:

i³².1

i²⁵.i

i⁸⁶.-1

i⁵¹.-i/0

8 0
3 years ago
Which mathematical property is demonstrated?!<br> If W<br> -8 and -8=u then wou
Ghella [55]

Step-by-step explanation:

64 bro

4 0
3 years ago
Fractions that are less than 1 and fractions that is greater than 1
DochEvi [55]
1/2 is less than 1
4/3 is more than 1
4 0
3 years ago
????⃗ (x,y)=(3x−4y)????⃗ +2x????⃗ F→(x,y)=(3x−4y)i→+2xj→ and ????C is the counter-clockwise oriented sector of a circle centered
Karolina [17]

By Green's theorem, the integral of \vec F along C is

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_D\left(\frac{\partial(2x)}{\partial x}-\frac{\partial(3x-4y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=6\iint_D\mathrm dx\,\mathrm dy

which is 6 times the area of D, the region with C as its boundary.

We can compute the integral by converting to polar coordinates, or simply recalling the formula for a circular sector from geometry: Given a sector with central angle \theta and radius r, the area A of the sector is proportional to the circle's overall area according to

\dfrac A{\frac\pi3\,\rm rad}=\dfrac{16\pi}{2\pi\,\rm rad}\implies A=\dfrac{8\pi}3

so that the value of the integral is

\dfrac{6\times8\pi}3=\boxed{16\pi}

6 0
4 years ago
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