I need help finding how this would work with numerical relationships x^3-3x^2+3xy^2-y^3=(x-y)^3
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Step by step explanation
I’m not too sure if I did it correct, but the answer I got was -6x^2+36. I just assumed you’d solve it as usual and then multiply (-3) after distributing-2 to x^2-6. Hope this helps.
