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wolverine [178]
3 years ago
11

I need help finding how this would work with numerical relationships x^3-3x^2+3xy^2-y^3=(x-y)^3

Mathematics
1 answer:
diamong [38]3 years ago
7 0

Answer:

y=mx+b

Step-by-step explanation:

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7,000 is ten times as much as what number
Nezavi [6.7K]
700. To find out what number a value is ten times as much as, divide by 10.
5 0
3 years ago
Sara bought 4 pounds
Roman55 [17]

Answer:

$12.80

Step-by-step explanation:

Sara bought 4 pounds of coffee.

Each pound (lb) costs $3.20

To find the total cost, multiply the cost per pound ($3.20) with the amount of pounds Sara is going to buy (4):

4 x 3.20 = $12.80

$12.80 would be the total cost before tax.

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3 0
3 years ago
Read 2 more answers
I NEED HELP PLSSSSSSSS
AVprozaik [17]

Answer:

X >>>>> Y

–1 >>>> 16

0 >>>>> 8

1 >>>>> 4

2 >>>>> 2

3 >>>>> 1

Step-by-step explanation:

From the question given above,

y = 8 × (½)ˣ

When x = –1, y =?

y = 8 × (½)ˣ

y = 8 × (½)¯¹

y = 8 × 2

y = 16

When x = 1, y =?

y = 8 × (½)ˣ

y = 8 × (½)¹

y = 8 × ½

y = 4

When x = 2, y =?

y = 8 × (½)ˣ

y = 8 × (½)²

y = 8 × ¼

y = 2

When x = 3, y =?

y = 8 × (½)ˣ

y = 8 × (½)³

y = 8 × ⅛

y = 1

SUMMARY:

X >>>>> Y

–1 >>>> 16

0 >>>>> 8

1 >>>>> 4

2 >>>>> 2

3 >>>>> 1

4 0
2 years ago
[(b+3)÷(a–2)](−4) if a=−5, b=6
MAXImum [283]

Answer:

36/7

Step-by-step explanation:

{(6+3)/(-5-2)}(-4)

36/7

4 0
3 years ago
Answer please VVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVV
mezya [45]

\left[\begin{array}{ccc}3 & 9 \\\\ 5& -2\end{array}\right]+\left[\begin{array}{ccc}6 & 0\\\\ \!\!-8 & 4\end{array}\right]=\left[\begin{array}{ccc} 3+6 & 9+0 \\\\5-8 &-2+4 \end{array}\right] =\left[\begin{array}{ccc} 9& 9 \\\\ -3 & 2\end{array}\right]

6 0
2 years ago
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