Answer:
the parabola can be written as:
f(x) = y = a*x^2 + b*x + c
first step.
find the vertex at:
x = -b/2a
the vertex will be the point (-b/2a, f(-b/2a))
now, if a is positive, then the arms of the parabola go up, if a is negative, the arms of the parabola go down.
The next step is to see if we have real roots by using the Bhaskara's equation:
Now, draw the vertex, after that draw the values of the roots in the x-axis, and now conect the points with the general draw of the parabola.
If you do not have any real roots, you can feed into the parabola some different values of x around the vertex
for example at:
x = (-b/2a) + 1 and x = (-b/2a) - 1
those two values should give the same value of y, and now you can connect the vertex with those two points.
If you want a more exact drawing, you can add more points (like x = (-b/2a) + 3 and x = (-b/2a) - 3) and connect them, as more points you add, the best sketch you will have.
Answer:
Step-by-step explanation:
Assuming you are asking for
85,000,000 + 2.9 x 10^5 =
8.5 x 10^7 + 2.9 x 10^5 =
10^5 ( 8.5 x10^2 + 2.9) =
10^5 ( 850+2.9) =
10^5 ( 852.9) =
10^5 x 8.529 x 10 ^2=
8.529 x 10^7
or
85,000,000 + 2.9 x 10^5 =
85,000,000 + 290,000 =
85290000 =
8.529 x 10 ^7 (because we moved 7 spots to the left)
4a-2=a+4
+2 to both sides
4a=a+6
-a from both sides
3a=6
Answer:
s=15
r=10
Step-by-step explanation:
What we know)
The measure of a line is 180º
If two parrel lines are cut by a transversal, the corresponding angles are congruent (corresponding angles postulate)
What we can figure out)
The angle measuring 3r+3s and 6r+3s are on the same line, so
3r+3s+6r+3s=180
3r+3s and 6r+s are corresponding, so
3r+3s=6r+s
Solve)
Now, we just need to solve the equations.
3r+3s+6r+3s=180 can be condensed into 9r+6s=180 by combining like terms. Then, you can divide by 3 to get 3r+2s=60
3r+3s=6r+s can be turned into 2s=3r by subtracting 3r and s.
So we have 3r+2s=60 and 2s=3r
We can substitute 2s for 3r
2s+2s=60
4s=60
s=15
Then, we can plug s=15 into the equation
2(15)=3r
30=3r
r=10
