In the year 2003, a person bought a new car for $18500. For each consecutive year after that, the value of the car depreciated b

Question

3 years ago

5

y 12%. How much would the car be worth in the year 2005, to the nearest hundred dollars?

2 answers:

eduard · Answer 1 · 2022-04-01T13:10:34+03:00

Answer:

$14300.00

Step-by-step explanation:

100 - 12 = 88%

88% = 0.88

$18500 x 0.88² = $14326.40

To the nearest hundread:

$14326.40 = $14300.00

0.88² means to the power of 2 since it is 2 consecutive years I did to the power of 2. If it was 3 consecutive years then you do 0.88³.

Hope this helps!

ki77a [65] · Answer 2 · 2022-04-01T10:44:30+03:00

ki77a [65]3 years ago

4 0

Answer:

Step-by-step explanation:

t is the number of years since 2003.

f(t) = $18,500×0.88^t

t = 2 in 2005

f(2) = $18,500×0.88²≅ $14,300