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4 years ago

8

6th grade math! Help me please :))

1 answer:

fenix001 [56]4 years ago

7 0

Answer: d 3 * 1/4

Step-by-step explanation:

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Can you just give me the equation to it?

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3 years ago

The length of a rectangle is 5 inches more than its width, x. The area of a rectangle can be represented by the equation x 2 + 5

Arada [10]

Answer:

Width = 15 inches Length = 20 inches

Step-by-step explanation:

The area of a rectangle is calculated using the following formula.

$A = Lx$ (1)

Where L is the length and x is the width of the rectangle

In this case we know that the length of the rectangle is 5 inches greater than its width. This means that:

$L = x + 5$ (2)

Also The area of a rectangle can be represented by the equation $x^2 + 5x = 300$

so to find the width x we solve the equation

$x^2 + 5x -300=0$ (3)

For an equation of the form $ax ^ 2 + bx + c = 0$ the quadratic formula is:

$x=\frac{-b\±\sqrt{b^2-4ac}}{2a}$

In this case note that:

$a=1\\b=5\\c=-300$

Then:

$x=\frac{-5\±\sqrt{(5)^2-4(1)(-300)}}{2(1)}$

$x=\frac{-5\±\sqrt{25+1200}}{2}$

$x=\frac{-5\±\sqrt{1225}}{2}$

$x=\frac{-5\±35}{2}$

$x_1=\frac{-5+35}{2}$ → $x_1=15$

$x_2=\frac{-5-35}{2}$ → $x_2=-20$

We take the positive solution $x=15\ in$

Now we use equation (2) to find L

$L = x + 5$

$L = 15 + 5$

$L = 20\ in$

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4 years ago

Evaluate the function at the given values<br> F(y) = 4y^4 - 6y^2 + 8y - 15<br> At y = 2

otez555 [7]

F(2)= 4(16) - 6(4) + 8(2) - 15
F(2)= 64 -24 + 16 - 15
F(2)= 41

7 0

3 years ago