Answer:
(a) It costs $55 at Happy Fruiterer
(b) It will cost $49.64
(c) It is cheaper at Happy Fruiterer the second week
Step-by-step explanation:
Since Fruitz shop sells as 10% less than Happy Fruiterer at $50
10% more of $50 = 50 × 10/100 + 50
= $5 + $50 = $55
(a) n Kg of grapes will cost $55 at Happy Fruiterer
(b) if Happy Fruits discounts $55 by 5%, we will have
55 × 5/100 = 2.75
that is $55 - $2.75 = $52.25
If it is discounted further at 5% more the following week, we will have
$52.25 × 5/100 = $2.6125
≈ $2.61
Then the new price for the 2nd week is $52.25 - $2.61
= $49.64
(c) at the second wee of discounting, Fruitz shop still sells at $50 will Happy Fruiterer now see at $49.64. Therefore, it is cheaper at Happy Fruiterer
Answer:
a negative slope is like this net.
OK. I did it, and I have the solution.
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The length of the deck is (5 + 2x) .
The width of the deck is (4 + 2x) .
If the deck didn't have that big hole in the middle where the pool is,
then its area would be
(5 + 2x) · (4 + 2x) .
When you multiply that all out, you get Area = 4x² + 18x + 20
and the question tells us that the area of the whole big rectangle is 90 yds² .
So we can write
4x² + 18x + 20 = 90 .
Subtract 90 from each side: 4x² + 18x - 70 = 0
Divide each side by 2 : 2x² + 9x - 35 = 0
You can use the quadratic equation to solve that and find out that
x = 2.5 yards, and that's what the question is asking you.
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That makes the deck 10 yds high and 9 yds wide.
Total area of the whole big rectangle, (deck + pool ), = 90 yds².
Answer:
![P = 0.1447](https://tex.z-dn.net/?f=P%20%3D%200.1447)
Step-by-step explanation:
Given
-- total
--- defective
--- selected
Required
The probability of rejecting the batch
This means that at least one of the selected piece is defected.
So, we first calculate the probability that all the selected piece are accepted.
So, we have:
![Pr = \frac{7000 - 180}{7000} * \frac{6999 - 180}{6999}* \frac{6998 - 180}{6998}* \frac{6997 - 180}{6997}* \frac{6996 - 180}{6996}* \frac{6995 - 180}{6995}](https://tex.z-dn.net/?f=Pr%20%3D%20%5Cfrac%7B7000%20-%20180%7D%7B7000%7D%20%2A%20%5Cfrac%7B6999%20-%20180%7D%7B6999%7D%2A%20%5Cfrac%7B6998%20-%20180%7D%7B6998%7D%2A%20%5Cfrac%7B6997%20-%20180%7D%7B6997%7D%2A%20%5Cfrac%7B6996%20-%20180%7D%7B6996%7D%2A%20%5Cfrac%7B6995%20-%20180%7D%7B6995%7D)
The denominator decreases by 1 because it is a probability without replacement; 180 is subtracted from the numerator to represent the number of non-defective CDs
So, we have:
![Pr = \frac{6820}{7000} * \frac{6819}{6999}* \frac{6818}{6998}* \frac{6817}{6997}* \frac{6816}{6996}* \frac{6815}{6995}](https://tex.z-dn.net/?f=Pr%20%3D%20%5Cfrac%7B6820%7D%7B7000%7D%20%2A%20%5Cfrac%7B6819%7D%7B6999%7D%2A%20%5Cfrac%7B6818%7D%7B6998%7D%2A%20%5Cfrac%7B6817%7D%7B6997%7D%2A%20%5Cfrac%7B6816%7D%7B6996%7D%2A%20%5Cfrac%7B6815%7D%7B6995%7D)
![Pr = 0.8553](https://tex.z-dn.net/?f=Pr%20%3D%200.8553)
Using the complement rule, the probability that the batch will be rejected is:
![P = 1 - 0.8553](https://tex.z-dn.net/?f=P%20%3D%201%20-%200.8553)
![P = 0.1447](https://tex.z-dn.net/?f=P%20%3D%200.1447)
Answer:
y= -a/bx +c/b
m= -a/b
b= c/b
Step-by-step explanation:
Hope this helps