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andrey2020 [161]

3 years ago

11

There is a population of 56,950 bacteria in a colony. If the number of bacteria doubles every 370 hours, what will the populatio

n be 1,850 hours from now?

2 answers:

almond37 [142]3 years ago

6 0

Answer:

100° it has to be a

length of 20 or like my 100 worlds longest

Irina18 [472]3 years ago

4 0

Answer:

370×1850= 6,84,500

and then

56,950+6,84,500=7,41,450

the population will be 7,41,450

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How do I confirm that f and g are inverses?

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Answer:

see explanation

Step-by-step explanation:

To show f and g are inverses we require to show that

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4 years ago

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aleksklad [387]

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3 years ago

Engineers must consider the diameters of heads when designing helmets. The company researchers have determined that the populati

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Answer:

1. The minimum head breadth that will fit the clientele is of 4.41-in.

2. The maximum head breadth that will fit the clientele is of 7.19-in.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of 5.8-in and a standard deviation of 0.8-in.

This means that $\mu = 5.8, \sigma = 0.8$

1. What is the minimum head breadth that will fit the clientele?

The 4.1st percentile, that is, X when Z has a pvalue of 0.041, so X when Z = -1.74.

$Z = \frac{X - \mu}{\sigma}$

$-1.74 = \frac{X - 5.8}{0.8}$

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The minimum head breadth that will fit the clientele is of 4.41-in.

2. What is the maximum head breadth that will fit the clientele?

100 - 4.1 = 95.9th percentile, that is, X when Z has a pvalue of 0.959, so X when Z = 1.74.

$Z = \frac{X - \mu}{\sigma}$

$1.74 = \frac{X - 5.8}{0.8}$

$X - 5.8 = 1.74*0.8$

$X = 7.19$

The maximum head breadth that will fit the clientele is of 7.19-in.

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3 years ago