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andrey2020 [161]
3 years ago
11

There is a population of 56,950 bacteria in a colony. If the number of bacteria doubles every 370 hours, what will the populatio

n be 1,850 hours from now?
Mathematics
2 answers:
almond37 [142]3 years ago
6 0

Answer:

100° it has to be a

length of 20 or like my 100 worlds longest

Irina18 [472]3 years ago
4 0

Answer:

370×1850= 6,84,500

and then

56,950+6,84,500=7,41,450

the population will be 7,41,450

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Help<br> me please asap
enot [183]

Answer:

first one:

Area of a circle = π*r²

diameter (they gave) = 30ft

radius = diameter/2 = 15ft

π*15²= 706.85834705770347865409476123789‬

to nearest tenth= 706.9 ft

second question:

circumference = 2*π*r or d(diameter)*π

diameter = 30ft

30*π = circumference = 94.247779607693797153879301498385‬

in terms of π = 30π

4 0
3 years ago
The sides of a square are increased by a scale factor of 6. The perimeter of the smaller square is 10 ft. What is the perimeter
inn [45]

Answer:

60ft

Step-by-step explanation:

I have not  done this kind of work in a while but if you scale each side of the square by 6 is should increase to a perimeter of 60ft

4 0
3 years ago
What is the approximate area of a circle with a diameter of 28 centimeters? Use π = 3.14.
larisa [96]
Formula is π * r^2

π = about 3.14 and the radius is half of the diameter so 28/2 = 14

3.14 * 14^2 = 615.44

B

8 0
3 years ago
Read 2 more answers
16) Please help with question. WILL MARK BRAINLIEST + 10 POINTS.
Katyanochek1 [597]
We will use the sine and cosine of the sum of two angles, the sine and consine of \frac{\pi}{2}, and the relation of the tangent with the sine and cosine:

\sin (\alpha+\beta)=\sin \alpha\cdot\cos\beta + \cos\alpha\cdot\sin\beta&#10;&#10;\cos(\alpha+\beta)=\cos\alpha\cdot\cos\beta-\sin\alpha\cdot\sin\beta

\sin\dfrac{\pi}{2}=1,\ \cos\dfrac{\pi}{2}=0

\tan\alpha = \dfrac{\sin\alpha}{\cos\alpha}

If you use those identities, for \alpha=x,\ \beta=\dfrac{\pi}{2}, you get:

\sin\left(x+\dfrac{\pi}{2}\right) = \sin x\cdot\cos\dfrac{\pi}{2} + \cos x\cdot\sin\dfrac{\pi}{2} = \sin x\cdot0 + \cos x \cdot 1 = \cos x

\cos\left(x+\dfrac{\pi}{2}\right) = \cos x \cdot \cos\dfrac{\pi}{2} - \sin x\cdot\sin\dfrac{\pi}{2} = \cos x \cdot 0 - \sin x \cdot 1 = -\sin x

Hence:

\tan \left(x+\dfrac{\pi}{2}\right) = \dfrac{\sin\left(x+\dfrac{\pi}{2}\right)}{\cos\left(x+\dfrac{\pi}{2}\right)} = \dfrac{\cos x}{-\sin x} = -\cot x
3 0
3 years ago
Can u get the steps to solving <br> -2(4)^2+4
svp [43]
(4)^2 must be done first.

That’ll give you 16. (4x4)

16 x -2= -32

-32+4= -28
8 0
3 years ago
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