At many golf clubs, a teaching professional provides a free 10-minute lesson to new customers. A golf magazine reports that go
lf facilities that provide these free lessons gain, on average, $2 comma 100 in green fees, lessons, or equipment expenditures. A teaching professional believes that the average gain exceeds $2 comma 100. Complete parts a through c below. a. In order to support the claim made by the teaching professional, what null and alternative hypotheses should you test? Upper H 0: mu equals $2 comma 100 Upper H Subscript a: mu greater than $2 comma 100 b. Suppose you select alphaequals0.01. Interpret this value in the words of the problem. The probablility that the null hypothesis is ▼ when the average gain ▼ is is not is less than exceeds $2 comma 100 is 0.01. c. For alphaequals0.01, specify the rejection region of a large-sample test. Choose the correct answer below. A. z less than minus 2.33 B. z less than minus 2.575 or z greater than 2.575 C. zless thanminus1.28 D. zless thanminus1.96 or zgreater than1.96 E. minus2.575less thanzless than2.575 F. z greater than 2.33 G. minus1.96less thanzless than1.96 H. zgreater than1.28
a) The objective of the study is test the claim that the average gain in the green fees , lessons or equipment expenditure for participating golf facilities is less than $2,100 under the claim the null and alternative hypothesis are,
H₀ : μ = $2,100
H₀ : μ < $2,100
B) Suppose you selects α = 0.01
The probability that the null hypothesis is rejected when the average gain is $2,100 is 0.01
C) For α = 0.01
specify the rejection region of a large sample test
At the given level of significance 0.01 and the test is left-tailed then rejection level of a large-sample = < - 1.28
First compute the perimeter of the pool: (21+33)*2=108 foot. Since the material cover 232 ft^2, then it is sufficient to divide the above number over the length of the border like this: 232/108=2.1
