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Xelga [282]
3 years ago
7

jane leaves her bicycle at 8:00 AM, traveling at an average speed of 15mph. her brother frank leaves home in his car at 10:30 AM

, traveling the same route as Jane at an average speed of 40 mph. at what time will they meet? i will give brainliest
Mathematics
2 answers:
mafiozo [28]3 years ago
4 0

Answer: 11:00

Step-by-step explanation:

IceJOKER [234]3 years ago
4 0

Answer: 11:00

Step-by-step explanation:

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Question<br> Evaluate the expression.<br><br> (−112)2
denis23 [38]

Answer:

1/144

step explanation:

(-1/12)^2 is -1/12 multiplied by itself twice. When multiplying fractions you can multiply straight across. When two negatives are multiplied together it makes a positive, so the answer is 1/144.

4 0
2 years ago
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1000x8129= WILL MAKR BRANLYEST
8_murik_8 [283]

Answer:

it is 8,129,000

Step-by-step explanation:

1000x8129 = 8,129,000

8 0
3 years ago
1. Oceanside Bike Rental Shop charges 13 dollars plus 6 dollars an
umka21 [38]
It cost 3$ per hour
3 0
4 years ago
Help with number 7!! You don’t have to do it but how do you do the problem??
musickatia [10]
80 * 5/8 will give you how many are thoroughbreds. 

80 * 5/8 = 50

Now subtract this from all of the horses. 

80 - 50 = 30. 

There are 30 quarter horses. 

OR If 5/8 of the horses are thoroughbreds, then 3/8 are quarter horses.

80 * 3/8 = 30. 
6 0
3 years ago
Read 2 more answers
Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.
fredd [130]

\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}

\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}

so the ODE is indeed exact and there is a solution of the form F(x,y)=C. We have

\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)

\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)

f'(y)=0\implies f(y)=C

\implies F(x,y)=x^2y^3+\ln(x+y^2)=C

With y(1)=2, we have

8+\ln9=C

so

\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}

8 0
3 years ago
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