We are given that the
coordinates of the vertices of the rhombus are:
<span><span>A(-6, 3)
B(-4, 4)
C(-2, 3)
D(-4, 2)
To solve this problem, we must plot this on a graphing paper or graphing
calculator to clearly see the movement of the graph. If we transform this by
doing a counterclockwise rotation, then the result would be:
</span>A(-6, -3)</span>
B(-4, -4)
C(-2, -3)
D(-4, -2)
And the final
transformation is translation by 3 units left and 2 units down. This can still
be clearly solved by actually graphing the plot. The result of this
transformation would be:
<span>A′(6, -8)
B′(7, -6)
C′(6, -4)
D′(5, -6)</span>
First, subtract y2 - y1 to find the vertical distance. Then, subtract x2 - x1 to find the horizontal distance.
Formula to find distance given two points.
Square root (X2 - X1)^2 + (Y2 - Y1)^2
Xa Ya Xb Yb
A = (3, -4) B = (-1, 3)
Xa goes into X2 and Xb goes into X1
(3 - (-1))^2
Ya goes into Y2 and Yb goes into Y1
(-4 - 3)^2
Square root (3 - (-1))^2 + (-4 - 3)^2
Square root (4)^2 + (-7)^2
Square root 16 + 49
Square root 65
= 8.06
The error was Drako had (3 - 4)^2 when it should have been (3 - (-4))^2 because a positive is subtracting a negative.
Answer:
x = 37
Step-by-step explanation:
2x + 9 = 83
-9 -9
2x = 74
--- ----
2 2
x = 37
A regular trapezoid is shown in the picture attached.
We know that:
DC = minor base = 4
AB = major base = 7
AD = BC = lateral sides or legs = 5
Since the two legs have the same length, the trapezoid is isosceles and we can calculate AH by the formula:
AH = (AB - DC) ÷ 2
= (7 - 5) ÷ 2
= 2 ÷ 2
= 1
Now, we can apply the Pythagorean theorem in order to calculate DH:
DH = √(AD² - AH²)
= √(5² - 1²)
= √(25 - 1)
= √24
= 2√6
Last, we have all the information needed in order to calculate the area by the formula:

A = (7 + 5) × 2√6 ÷ 2
= 12√6
The area of the regular trapezoid is
12√6 square units.
Step-by-step explanation:
Whole numbers = Natural numbers + "0"
Integers = Whole numbers + Negative counterparts
Since the set do contains negative numbers, only Rational numbers and Integers are correct. (D)