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Paul [167]
3 years ago
7

Can anyone Answer this??

Mathematics
1 answer:
True [87]3 years ago
4 0
Parallel lines would have to have the same slope so the green line also has a 1/5 slope
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Above is a table with missing terms. Come up with a possible common difference that makes sense and list the missing terms.
Rina8888 [55]

Answer:

common ratio:2 2. 18  3.36  4.72 equation: 4.5(2^x)

Step-by-step explanation:

144=2*2*2*2*3*3    9=3*3

the common ratio would be 2

2. 9*2=18

3. 18*2=36

4. 36*2=72

(check) 72*2=144

0. 9/2=4.5

equation: 4.5(2^x)

7 0
2 years ago
Witch of the following Represents the distance between 4/3 and 1/3
marishachu [46]

Answer:

1

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
-5(6v-w-1) <br> Distributive prot
krok68 [10]

Answer:

-30v + 5w + 5

Step-by-step explanation:

-5(6v - w - 1) =

Multiply -5 by each term inside the parentheses.

= -5 * 6v - (-5) * w - (-5) * (-1)

= -30v + 5w + 5

5 0
3 years ago
What are the coordinates of the midpoint of the line segment with endpoints R(4,−7) and S(−3,5)?
tekilochka [14]
The answer is (.5,-1)
3 0
3 years ago
Part of the graph of the function f(x) = (x – 1)(x + 7) is shown below.Which statements about the function are true? Select thre
sertanlavr [38]

The statements about the function that are true are

  • The vertex of the function is at (–3,–16).
  • The graph is increasing on the interval x > –3.
  • The graph is positive only on the intervals where x < –7 and where x > 1.

<h3>How to interpret the graph?</h3>

The equation of the graph is given as

f(x) = (x - 1)(x + 7)

The graph of the function is added as an attachment

On the graph, we have

Vertex = (-3, -16)

This is so because the graph has a minimum point of (-3, -16)

Also, the graph crosses the x-axis at x = 1 and x = -7

This means that the graph is positive at x >1 and x >-7

Because the vertex is a minimum, the graph is increasing at the left of its symmetry i.e. x > -3

Read more about quadratic functions at

brainly.com/question/14933288

#SPJ1

7 0
1 year ago
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