F(x)=4+6+5/4+1
F(x)=4+6+5/5
F(x)=10+1=11
Answer =11
<span>So far I have:
(1.25 + 1) </span><span>if </span>x<span> is in the interval</span><span> (-inf,7]
(2.25 +1) </span><span>if </span>x<span> is in the interval (7,13)</span><span>
(3.50+1+3) </span><span>if </span>x<span> is in the interval [13,inf)</span>
144 classes. each class is 10 minutes. 6X24= 144
We know that this is a parabola, as the equation is denoted by the x^2 term.
We can see that the symmetry is seen at the point -0.5, therefore making the axis of symmetry the vertical line -0.5.
The vertex is found in quadrant three. In other words, it will shift by a negative value both horizontally and vertically. The vertex is therefore (-0.5, -0.5).
We can verify this in the equations by using the formula (-b/2a) to find the vertex. The only quadratic equation that satisfies this is -2x^2 + 2x -1.
To sum it up, the answers are:
-2x^2 + 2x - 1.
AoS: x = -0.5
Vertex: (-0.5, -0.5).
