Fine the slope of the line in simplest form.

The president of the student council wants to survey the student population. She decides to take a random sample of

OlgaM077 [116]

Using sampling concepts, it is found that the correct option regarding if this is a random sample is given by:

Yes, because the slips of paper were all the same shape and size.

<h3>How are samples classified?</h3>

Samples may be classified as:

Convenient: Drawn from a conveniently available pool.
Random: All the options into a hat and drawn some of them.
Systematic: Every kth element is taken.
Cluster: Divides population into groups, called clusters, and each element in the cluster is surveyed.
Stratified: Also divides the population into groups. Then, a equal proportion of each group is surveyed.

In this problem, since the slips have the same shape and size, each name has an equal probability of being chosen, hence it is a random sample and the correct option is:

Yes, because the slips of paper were all the same shape and size.

More can be learned about sampling concepts at brainly.com/question/25122507

4 0

2 years ago

Please help if you can

umka21 [38]

Answer: 80, 1/12, 5/6

Step-by-step explanation:

7 0

3 years ago

According to a research center, 16% of all merchandise sold in a particular country gets returned. A department store in a certa

Mamont248 [21]

Answer:

a) point estimate of the proportion of items returned for the population of sales transactions at the store in the given city

Point estimate = 0.3

b) The 95% confidence interval for the proportion of returns at the store in the given city

( 0.19958,0.40042)

Step-by-step explanation:

Given the Population proportion 'P'= 16% = 0.16

Given data a department store in a certain city sampled 80 items sold in January and found that 24 of the items were returned

The sample proportion $p = \frac{x}{n}$

here x =24 and n = 80

The sample proportion $p = \frac{x}{n} = \frac{24}{80} = 0.3$

a)<u> Point estimate</u>:-

A point estimate of the true proportion P

Point estimate = $p = \frac{x}{n}$

point estimate of the proportion of items returned for the population of sales transactions at the store in the given city

$p = \frac{x}{n} = \frac{24}{80} = 0.3$

b) <u>The 95% confidence interval for the proportion </u>

The 95% confidence interval for the proportion of returns at the store in the given city

$(p - z_{\alpha } \sqrt{\frac{p(1-p)}{n} } , p + z_{\alpha }\sqrt{\frac{p(1-p)}{n} } )$

substitute all values we get ,

$(0.3 - 1.96 \sqrt{\frac{0.3(1-0.3)}{80} } , 0.3 + 1.96\sqrt{\frac{0.3(1-0.3)}{80} } )$

on simplification, we get

(0.3-0.10042 ,0.3+0.10042)

( 0.19958,0.40042)

<u>Conclusion</u>:-

a) point estimate of the proportion of items returned for the population of sales transactions at the store in the given city

Point estimate = 0.3

b) The 95% confidence interval for the proportion of returns at the store in the given city

( 0.19958,0.40042)

5 0

4 years ago

Select the correct answer.

nignag [31]

I think it’s B. 4 because 65 divides by 15

3 0

3 years ago

Read 2 more answers

The weekly salaries of a sample of employees at the local bank are given in the table below. Employee Weekly Salary Anja $245 Ra

Bond [772]

1st Step - Find the mean (average):
245 + 300 + 325 + 465 + 100 = 1435
1435/5 = 287 ( mean)

2nd step find the sun of the sqaure the difference between the gievn data and the mean

287 - 245 = 42^2 = 1,764
300 - 387 = 13^2 = 169
325-287 = 38^2 = 1,444
465 - 287 = 178^2 = 31,684
287 - 100 = 187^2 = 34,969

1,764 +169 + 1,444 + 31,684 + 34,969 = 70,030

Now divide that by the number of samples minus 1 ( 5-1=4)

70,030 / 4 = 17,507.5

The variance = 17, 507.5

6 0

3 years ago