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Paladinen [302]
2 years ago
13

27 is 3 as many times aswhat number

Mathematics
2 answers:
REY [17]2 years ago
8 0

Answer:

9

Step-by-step explanation:

27 divided by 3 is 9

Andru [333]2 years ago
3 0
27 is 3 as many times the number 9
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devlian [24]
11.52 72×3=216x48÷100÷9= 11.52
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3 years ago
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Marcus is observing bacteria multiply.every 15 seconds,there are 10 times more bacteria than before.if there are 10 bacteria now
r-ruslan [8.4K]
No he is wrong  there will be 150000000 bacteria on it at 2 minutes

WORK:

2 min=120 sec
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The number of students enrolled at a college is 15,000 and grows 4% each year
Kipish [7]

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15,000

Step-by-step explanation:

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2 years ago
Place the indicated product in the proper location on the grid. (x + y)(x2 - xy + y2)
mihalych1998 [28]

Answer:

I am truly sorry

Step-by-step explanation:

3 0
3 years ago
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At time t ≥ 0, the velocity of a body moving along the s-axis is v = t² -5t +4. When is the body moving backwards
katovenus [111]

Answer:

A

Step-by-step explanation:

The velocity of a moving body is given by the equation:

v=t^2-5t+4 ,\, t\geq0

Is the velocity is <em>positive </em>(v>0), then our object will be moving <em>forwards</em>.

And if the velocity is negative (v<0), then our object will be moving <em>backwards</em>.

We want to find between which interval(s) is the object moving backwards. Hence, the second condition. Therefore:

v

By substitution:

t^2-5t+4

Solve. To do so, we can first solve for <em>t</em> and then test values. By factoring:

(t-4)(t-1)=0

Zero Product Property:

t=1, \text{ and } t=4

Now, by testing values for t<1, 1<t<4, and t>4, we see that:

v(0)=4>0,\, v(2)=-20

So, the (only) interval for which <em>v</em> is <0 is the second interval: 1<t<4.

Hence, our answer is A.

7 0
3 years ago
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