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3 years ago

What is the name of this polygon?

Mathematics

2 answers:

kipiarov [429]3 years ago

8 0

That should be a pentagon. 5 sides. Hexagons have 7, I believe, and quadrilaterals have 4

Aleksandr [31]3 years ago

7 0

Answer:

i believe it is a hexagon, since it has 5 sides

You might be interested in

15 - m ≥ 4<br><br> if m = 11<br><br> true or false

Dominik [7]

Answer:

false

because its equal

15 - 11 = 4

4 = 4

4 0

3 years ago

A grocery store sells steak for $6.10 per pound. What would be the cost of 2 3/5 pounds of steak?

jonny [76]

The answer is $15.86

You find this by doing 2 and 3/5 or 2.6 times 6.10 getting an answer of $15.86

5 0

4 years ago

Which equation is y = 3(x – 2)2 – (x – 5)2 rewritten in vertex form?

hichkok12 [17]

  y = 3(x - 2)² - (x - 5)²
  y = 3(x - 2)(x - 2) - (x - 5)(x - 5)
y = 3(x(x - 2) - 2(x - 2)) - (x(x - 5) - 5(x - 5))
y = 3(x(x) - x(2) - 2(x) + 2(2)) - (x(x) - x(5) - 5(x) + 5(5))
y = 3(x² - 2x - 2x + 4) - (x² - 5x - 5x + 25)
y = 3(x² - 4x + 4) - (x² - 10x + 25)
y = 3(x²) - 3(4x) + 3(4) - (x²) + (10x) - (25)
y = (3x² - 12x + 12) + (-x² + 10x - 25)
y = (3x² - x²) + (-12x + 10x) + (12 - 25)
y = 2x² - 2x - 13
  + 13 + 13
y + 13 = 2x² - 2x + 0.5
y + 13 + 0.5 = 2(x² - x + 0.25)
y + 13.5 = 2(x² - 0.5x - 0.5x + 0.25)
y + 13.5 = 2(x(x) - x(0.5) - 0.5(x) + 0.5(0.5))
y + 13.5 = 2(x(x - 0.5) - 0.5(x - 0.5))
y + 13.5 = 2(x - 0.5)(x - 0.5)
y + 13.5 = 2(x - 0.5)²
- 13.5 - 13.5
y = 2(x - 0.5)² - 13.5

7 0

3 years ago

Read 2 more answers

Write the point-slope form of the equation of the line through the given point with the given

Marina86 [1]

Question 3)

Given

The point (1, -5)

The slope m = -5/6

Using the point-slope form of the equation of a line

$y-y_1=m\left(x-x_1\right)$

where

m is the slope of the line

(x₁, y₁) is the point

In our case:

m = -5/6

(x₁, y₁) = (1, -5)

substituting the values m = -5/6 and the point (1, -5) in the point-slope form of the equation of the line

$y-y_1=m\left(x-x_1\right)$

$y-\left(-5\right)=-\frac{5}{6}\left(x-1\right)$

$y+5=-\frac{5}{6}\left(x-1\right)$

Thus, the point-slope form of the equation of the line is:

$y+5=-\frac{5}{6}\left(x-1\right)$

Question 4)

Given

The point (-1, 5)

The slope m = -7/2

In our case:

m = -7/2

(x₁, y₁) = (-1, 5)

substituting the values m = -7/2 and the point (-1, 5) in the point-slope form of the equation of the line

$y-y_1=m\left(x-x_1\right)$

$y-5=-\frac{7}{2}\left(x-\left(-1\right)\right)$

$y-5=-\frac{7}{2}\left(x+1\right)$

Thus, the point-slope form of the equation of the line is:

$y-5=-\frac{7}{2}\left(x+1\right)$

7 0

3 years ago

Of the 1,400 students enrolled at a Middle School, 40% of students enrolled are in the 6th grade. How many students are enrolled

scZoUnD [109]

Answer:

560 students

Step-by-step explanation:

1400*.40=560 students in 6th grade

8 0

4 years ago