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Cloud [144]
3 years ago
15

Is 5 a irrational number

Mathematics
2 answers:
masha68 [24]3 years ago
8 0
<h2>Answer:</h2>

No. Because, 5 is an integer, that's why it's not irrational.

AfilCa [17]3 years ago
6 0

Answer:

no.

Step-by-step explanation:

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Which of these choices are square roots of 144? Check all that apply. ​
zepelin [54]

Answer:

E

Step-by-step explanation:

3 0
3 years ago
KX equals X +4 find K7
Andre45 [30]
KX = x+4 so solve for k. 
Divide both sides of the equation by x and you get K=4. 
Plug it in, and you get (4)(7)=28
Your answer is 28.
5 0
3 years ago
2(2x – 1) + 7 &lt; 13 or –2x + 5≤-10
e-lub [12.9K]

Answer:

2, 7.5

Step-by-step explanation:

2(2x - 1) + 7 < 13

4x - 2 + 7 < 1

4x + 5 < 13

4x < 8

x < 2

-2x + 5 ≤ -10

-2x ≤ -10 - 5

-2x ≤ -15

x ≤ -15 / -2

x ≤ 7.5

4 0
2 years ago
Can you help me please!
Lostsunrise [7]

9514 1404 393

Answer:

  Lanza is correct.

Step-by-step explanation:

The two missing dimensions on the left are 4.5 m on the vertical line, and 5 m on the horizontal line.

These dimensions let us partition the garden a number of ways. One way is ...

  • a rectangle 9 m by 4.5 m
  • a rectangle 4 m by 3.5 m

The total of the areas of these is ...

  (9)(4.5) +4(3.5) = 40.5 +14 = 54.5 . . . . square meters

At £16 per square meter, Lanza's charge will be ...

  £16 × 54.5 = £872

Lanza is correct that she will have to charge more than £800.

8 0
3 years ago
The endpoints of `bar(EF)` are E(xE , yE) and F(xF , yF). What are the coordinates of the midpoint of `bar(EF)`?
Hoochie [10]

For a better understanding of the solution provided here please find the diagram attached.

Please note that in coordinate geometry, the coordinates of the midpoint of a line segment is always the average of the coordinates of the endpoints of that line segment.

Thus, if, for example, the end coordinates of a line segment are (x_{1}, y_1) and (x_2, y_2) then the coordinates of the midpoint of this line segment will be the average of the coordinates of the two endpoints and thus, it will be:

(\frac{(x_1+x_2)}{2}, \frac{(y_1+y_2)}{2})

Thus for our question the endpoints are (x_E, y_E) and (x_F, y_F) and hence the midpoint will be:

(x_M, y_M)=(\frac{(x_E+x_F)}{2}, \frac{(y_E+y_F)}{2})

Thus, Option C is the correct option.

6 0
4 years ago
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