All categories

2 years ago

Using mixed numbers, write a problem in which an estimate is enough to solve the problem.

Mathematics

1 answer:

KengaRu [80]2 years ago

7 0

explain:

Estimating Differences of Fractions and Mixed Numbers

Estimating Differences of Fractions and Mixed NumbersRecall that estimation is a method for finding an approximate solution to a problem. Even when you are asked to find an exact ko, estimation is a useful way to get an idea of a reasonable solution to a problem. Once you have found an exact answer, you can check your answer against the estimate.

, estimation is a useful way to get an idea of a reasonable solution to a problem. Once you have found an exact answer, you can check your answer against the estimate.When working with fractions and mixed numbers, you can use the fraction benchmarks of 0, 12, and 1 to help you to estimate differences.

You might be interested in

Halla la tasa de variación de cada funcion en el intervalo [-4,3] e indica si es positiva , negativa o nula A) f(x)=x2-2x+4 B) f

masya89 [10]

Answer:

$A) \hspace{3}Rate\hspace{3}of\hspace{3}change=-5\hspace{3}Negative\\\\B)\hspace{3}Rate\hspace{3}of\hspace{3}change=-21\hspace{3}Negative$

Step-by-step explanation:

Given a function $f(x)$ , we called the rate of change to the number that represents the increase or decrease that the function experiences when increasing the independent variable from one value " $x_1$ " to another " $x_2$ ".

The rate of change of $f(x)$ between $x_1$ and $x_2$ can be calculated as follows:

$Rate\hspace{3}of\hspace{3}change=f(x_2)-f(x_1)$

For:

$f(x)=x^2-2x+4$

Let's find $f(x_1)$ and $f(x_2)$ , where:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=(-4)^2-2(4)+4=16-8+4=12\\f(x_2)=f(3)=(3)^2-2(3)+4=9-6+4=7$

So:

$Rate\hspace{3}of\hspace{3}change =7-12=-5\hspace{3}Negative$

And for:

$f(x)-3x+2$

Let's find $f(x_1)$ and $f(x_2)$ , where:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

So:

$Rate\hspace{3}of\hspace{3}change =-7-14=-21\hspace{3}Negative$

<em>Translation:</em>

Dada una función $f(x)$ , llamábamos tasa de variación al número que representa el aumento o disminución que experimenta la función al aumentar la variable independiente de un valor " $x_1$ " a otro " $x_2$ ".

La tasa de variación de $f(x)$ entre $x_1$ y $x_2$ , puede ser calculada de la siguiente forma:

$Tasa\hspace{3}de\hspace{3}variacion=f(x_2)-f(x_1)$

Para:

$f(x)=x^2-2x+4$

Encontremos $f(x_1)$ y $f(x_2)$ , donde:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

Entonces:

$Tasa\hspace{3}de\hspace{3}variacion =7-12=-5\hspace{3}Negativa$

Y para:

$f(x)-3x+2$

Encontremos $f(x_1)$ y $f(x_2)$ , donde:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

Entonces:

$Tasa\hspace{3}de\hspace{3}variacion=-7-14=-21\hspace{3}Negativa$

8 0

3 years ago

What is the common ratio? {250, 50, 10, 2...}

Allisa [31]

Answer:

Step-by-step explanation:

The common ration can be found by dividing the 2nd number from the 1st number:

250 / 50

which equals 5

250 / 50 = 5

you can do this by any number, for example:

50 / 10 =5

10 / 2 = 5

6 0

3 years ago

Round your answer to the nearest whole dollar

sleet_krkn [62]

A.

First you have to evaluate (2000* .045) then you take that and multiply by 8 then you add the answer to 2000.

so 2720 is your answer.

5 0

2 years ago

A cylinder has a volume of 360 in^3. If the height and radius are multiplied by 2.5, what will the resulting volume be?

4vir4ik [10]

$\bf \textit{volume of a cylinder}\\\\
V=\pi r^2 h\quad 
\begin{cases}
r=radius\\
h=height\\
-----\\
r=2.5r\\
h=2.5h
\end{cases}\implies V=\pi (2.5r)^2(2.5h)
\\\\\\
V=\pi \cdot 2.5^2\cdot r^2\cdot 2.5h\implies V=(2.5^2\cdot 2.5)\pi r^2 h
\\\\\\
V=15.625\pi r^2h\impliedby \textit{15.625 of the original}
\\\\\\
\textit{if the original was 360}\qquad 15.265\cdot 360$

5 0

3 years ago

Is this right from greatest to least or do I have to change anything???

Alinara [238K]

Answer:

Yes its correct

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Using mixed numbers, write a problem in which an estimate is enough to solve the problem.​

Using mixed numbers, write a problem in which an estimate is enough to solve the problem.