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Mkey [24]
3 years ago
11

Find the area of this parallelogram8cm10cm14cm​

Mathematics
1 answer:
Natasha2012 [34]3 years ago
8 0

Answer:

112 cm^{2}

Step-by-step explanation:

A=bh

A=14*8

A=112

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What is the slope of the equation Y=5/4x-7/4?
maksim [4K]

Answer:

Step-by-step explanation:

Compare the equation with y = mx + b where m is slope and b is y intercept

y = (5/4)x - (7/4)

Slope = m = 5/4

4 0
2 years ago
In ΔABC, If AB=BC and ∠B=40∘,what is the measure of ∠C?
AlekseyPX

Answer:

70

Step-by-step explanation:

all angles in a triangle add up to 180

if two sides are equal their angles are equal

180-40

140÷2

70

7 0
2 years ago
Which equation is represented by the table?
enot [183]

Answer:

C??????????????? ?????????

7 0
2 years ago
The braking distance, in feet of a car a Travling at v miles per hour is given.
irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

  • The braking distance at 25 mph, is approximately <u>63.7 ft.</u>
  • The braking distance at 55 mph,  is approximately <u>298.35 ft.</u>
  • The braking distance at 85 mph,  is approximately <u>708.92 ft.</u>

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.

At 25 mph, the braking distance is approximately <u>63.7 ft.</u>

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945  ft.s

D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.

At 55 mph, the braking distance is approximately <u>298.35 ft.</u>

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.

At 85 mph, the braking distance is approximately <u>708.92 ft.</u>

b. The speed of the car when the braking distance is 450 feet is given as follows;

450 = 2.6 + \dfrac{v^2}{22}

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ <u>98.211 ft./s</u>

Learn more here:

brainly.com/question/18591940

8 0
2 years ago
Solve the system of linear equations by substitution.<br> y=X-4<br> - 2x+y= 18
11Alexandr11 [23.1K]

Answer:

] y=x-4

-2x+y=18

y - x = -4

y - 2x = 18

equation [2] for the variable y

[2] y = 2x + 18

// Plug this in for variable y in equation [1]

[1] (2x+18) - x = -4

[1] x = -22

// Solve equation [1] for the variable x

[1] x = - 22

// By now we know this much :

y = 2x+18

x = -22

// Use the x value to solve for y

y = 2(-22)+18 = -26

Step-by-step explanation:

please mark me as brainlist please

4 0
2 years ago
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