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Anni [7]
2 years ago
11

The time (in minutes) required to learn the procedure for performing a certain task is uniformly distributed on the interval fro

m 32 minutes to 52 minutes. (a) What is the probability that it takes more than 46 minutes to learn the procedure?(b) What is average time reqiured to learn the procedure?
Mathematics
1 answer:
PtichkaEL [24]2 years ago
3 0

Answer:

a

 P( X >  46)  = 0.7 \  minute

b

\mu  = 42 \ minute

Step-by-step explanation:

From the question we are told that  

   The procedure for performing a certain task is uniformly distributed on the interval from( a =  32 )minutes to (b= 52) minutes

  Generally the cumulative distribution function for continuous uniform distribution is  

             F(x) =  \left \{ {{0 \ \ \ \ \  for  \  x \  x < a} \atop {\frac{x-a}{b-a} } \ \   for \  a \le x \ge b} \atop {1 \ \ \ \ \ \ \  for  \  x  >  b }\right.

Generally the probability that it takes more than 46 minutes to learn the procedure is mathematically represented as

          P( X >  46)  = F(46) = \frac{46 - 32}{52-32}

=>       P( X >  46)  = 0.7 \  minute

Generally the average time required to learn the procedure is mathematically represented as

        \mu =  \frac{a + b}{2}

=>     \mu  =  \frac{32 + 52}{2}

=>     \mu  = 42 \ minute

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Answer:

  • <u><em>The solution to f(x) = s(x) is x = 2012. </em></u>

Explanation:

<u>Rewrite the table and the choices for better understanding:</u>

<em>Enrollment at a Technical School </em>

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<h2>Solution</h2>

The question requires to find which of the options represents the solution to f(x) = s(x).

That means that you must find the year (value of x) for which the two functions, the enrollment the first year, f(x), and the enrollment the second year s(x), are equal.

The table shows that the values of f(x) and s(x) are equal to 732 (students enrolled) in the year 2012,<em> x = 2012. </em>

Thus, the correct choice is the third one:

  • The solution to f(x) = s(x) is x = 2012.
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