Question

The percentage of people under the age of 18 was 23.5% in New York City, 25.8% in Chicago, and 26% in Los Angeles.

Answer 1

Answer:

0.0158 = 1.58% probability that all of them are under 18.

Step-by-step explanation:

Probability of independent events:

If three events, A, B and C are independent, the probability of all happening is the multiplication of the probabilities of each happening, that is:

$P(A \cap B \cap C) = P(A)P(B)P(C)$

The percentage of people under the age of 18 was 23.5% in New York City, 25.8% in Chicago, and 26% in Los Angeles.

This means that $P(A) = 0.235, P(B) = 0.258, P(C) = 0.26$

If one person is selected from each city, what is the probability that all of them are under 18?

Since the three people are independent:

$P(A \cap B \cap C) = 0.235*0.258*0.26 = 0.0158$

0.0158 = 1.58% probability that all of them are under 18.