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2 years ago

The percentage of people under the age of 18 was 23.5% in New York City, 25.8% in Chicago, and 26% in Los Angeles.

Mathematics

1 answer:

Hatshy [7]2 years ago

8 0

Answer:

0.0158 = 1.58% probability that all of them are under 18.

Step-by-step explanation:

Probability of independent events:

If three events, A, B and C are independent, the probability of all happening is the multiplication of the probabilities of each happening, that is:

$P(A \cap B \cap C) = P(A)P(B)P(C)$

The percentage of people under the age of 18 was 23.5% in New York City, 25.8% in Chicago, and 26% in Los Angeles.

This means that $P(A) = 0.235, P(B) = 0.258, P(C) = 0.26$

If one person is selected from each city, what is the probability that all of them are under 18?

Since the three people are independent:

$P(A \cap B \cap C) = 0.235*0.258*0.26 = 0.0158$

0.0158 = 1.58% probability that all of them are under 18.

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geniusboy [140]

Answer:

Step-by-step explanation:

So, I'm pretty sure this is a problem about compound interest.

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For this problem, $1000 is p, the initial amount; A is the total amount, or $1050.

What the problem is asking for is r, the interest rate, which is divided by n. N is the number of times the interest rate is compounded per year; Since the question is asking for the annual interest rate, N would be equal to 1. And because Terrence is has only left his money in for a year, t would also be equal to one.

So, by filling in the formula some, we get this:

$1050 = $1000(1 + r/1)^1*1

To find r, we would need to isolate it in the problem.

1. First, distribute $1000 to the parenthesis(keep in mind that 1000, is also equal to 1000/1:

1050 = (1000 + 1000r/1)^1

2. Then subtract 1000 from both sides:

50 = (1000r/1)^1

3. Multiple both sides by one:

50 = (1000r)^1

4. Divide both sides by 1000:

.05 = r^1 or .05 = r.

The answer is A, 5%.

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bija089 [108]

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