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3 years ago

Find the common ratio of the geometric sequence 6 , 24 , 96 , . . .

Mathematics

1 answer:

Lelu [443]3 years ago

7 0

Answer:

Step-by-step explanation:

6 * 4 = 24

24 * 4 = 96

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A group of church members chartered a bus for $832. After making the arrangements, 6 more members decided to join the excursion

g100num [7]

Let x = # of original members
Cost per person (originally) = 832/x
Cost per person after 6 more people = 832/(x+6)
Solve 832/x=832/(x+6) +6 (because the cost was reduced by 6
Solve for x.
x = 26 or -32 (but x is number of members, so it can't be negative)
# of original members is 26.
Original cost is 832/26 = $32 per person.

3 0

3 years ago

Huilan is 7 years younger than thomas the sum of their age is 59 what is thomas age

Tems11 [23]

Answer: Thomas is 33 years old

Step-by-step explanation:

59-7=52

52÷2=26

26+7=33

So therefore Thomas is 33 years old

5 0

3 years ago

Read 2 more answers

-2(8w+13)+9w=-61 what does w represent

zaharov [31]

-16w-26+9w=-61
-16w+9w=-61+26
-7w=-35
w=5

3 0

3 years ago

Read 2 more answers

ASAP HELP RN

Akimi4 [234]

Answer:

Part B: is -60 divided by -10

Part C: is The number of increments is positive.

Part D: is -1 times 60 / -1 times 10

Part E: is Any number divided by itself is 1. In the expression -1 times 60, the -1s in the numerator and the denominator cancel each other out to give the result 60/10, or 6

Part F: is There are 6 increments of -10 feet in -60 feet.

Part G is: copy and paste -10 feet 6 times

Part H: is -60 / 4 increments

Part I: is there is one negative number in the expression, so the solution will be negative. There isn't a -1 in the denominator to cancel out the -1 in the numerator.

Part J: is -60 /4 =-15 Alex’s elevation change in each increment was -15 feet.

Step-by-Step Explaination: I did the test.

6 0

4 years ago

In a bag of m&m's there are 5 brown 6 yellow 4 blue 3 green and 2 orange. What's the probability of getting 3 yellow m&m

olasank [31]

There are 5+6+4+3+2=20 m&m's in the bag.
Calculate in how many ways you can choose 3 m&m's from 20:
$_{20} C _3=\frac{20!}{3!(20-3)!}=\frac{20!}{3! \times 17!}=\frac{17! \times 18 \times 19 \times 20}{6 \times 17!}=\frac{18 \times 19 \times 20}{6}=3 \times 19 \times 20= \\
=1140$

There are 6 yellow m&m's.
Calculate in how many ways you can choose 3 m&m's from 6:
$_6 C _3 = \frac{6!}{3!(6-3)!}=\frac{6!}{3! \times 3!}=\frac{3! \times 4 \times 5 \times 6}{3! \times 6}=\frac{4 \times 5 \times 6}{6}=4 \times 5=20$

The probability is the number of ways of choosing 3 m&m's from 6 m&m's divided by the number of ways of choosing 3 m&m's from 20 m&m's.
$P=
\frac{20}{1140}=\frac{20 \div 20}{1140 \div 20}=\frac{1}{57}$

The probability is 1/57.

4 0

3 years ago