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sergij07 [2.7K]
3 years ago
12

Raymond works in an electronics store and gets a 12 percent employee discount. The original cost of a video game system is $175.

What is the discounted price of the game system?
Mathematics
2 answers:
vesna_86 [32]3 years ago
6 0
Since he got 12% discount,
% of the value =  100% - 12% = 88%

Discounted price = 88%  of  175 = (88/100) * 175

                             =   0.88 * 175 = 154

Discounted price = $154.
Masja [62]3 years ago
4 0
Well once I get out meh handy dandy calculator. I'm bad at explaining. 175 - 12% = 154. Hope it helps.
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Part A:

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-3 - (-11) = -3 + 11 = 8.

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Part B:

Consider from x = -3 to x = -1, they are 2 units apart and the difference of their outputs is given by:

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Thus, the value of the output increases by 16 units for each two units increase in the input.



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Consider from x = 0 to x = 3, they are 3 units apart and the difference of their outputs is given by:

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Thus, the value of the output increases by 24 units for each three units increase in the input.



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It can be noticed that the ratio difference in the outputs to the input intervals are equal for all the given input intervals.

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Hey everyone. I need the answer to this ASAP!: Michael knows that 2 cans of paint is the exact amount he needs to paint a 10-foo
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Answer:

See attachment for graph

<em></em>

Step-by-step explanation:

Given

2 cans = 10ft\ by\ 12ft

Required

Graph the relationship between both parameters

First, calculate the area;

Area = 10ft * 12ft

Area = 120ft^2

This implies that: (2, 120) i.e. 2 cans for 120ft^2.

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(0,0) and (2,120)

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<em>See attachment for graph</em>

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The Rocky Mountain district sales manager of Rath Publishing Inc., a college textbook publishing company, claims that the sales
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Answer:

t=\frac{44-42}{\frac{1.9}{\sqrt{40}}}=6.657    

p_v =P(t_{(39)}>6.657)=3.17x10^{-8}  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 42 at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=44 represent the sample mean

s=1.9 represent the sample standard deviation

n=40 sample size  

\mu_o =42 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 42, the system of hypothesis would be:  

Null hypothesis:\mu \leq 42  

Alternative hypothesis:\mu > 42  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{44-42}{\frac{1.9}{\sqrt{40}}}=6.657    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=40-1=39  

Since is a one side test the p value would be:  

p_v =P(t_{(39)}>6.657)=3.17x10^{-8}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 42 at 1% of signficance.  

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