We have an equation with two variables, so as we have a system with less equations (just one) than variables (two), we have an infinite number of solutions.
To find some solutions, we can choose values for x and then just calculate the value of y:
x = 0:
-11y = 10 -> y = -10/11
x = 1:
3 - 11y = 10 -> y = -7/11
x = 2:
6 - 11y = 10 -> y = -4/11
And so on.
So the correct option is c): infinitely many solutions
