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mihalych1998 [28]
3 years ago
9

HELP ASAP PLSSS TY TY TYY

Mathematics
1 answer:
Gnoma [55]3 years ago
6 0

Answer:

c

Step-by-step explanation:

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Please answer this question fast​
svetoff [14.1K]

Answer:

348 of them are not postgraduates

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
What is the total volume of pepsi in this pack of 12? Each cylindrical can has a radius of 1.25in and a height of 4.5in
Alecsey [184]
Total Volume of pepsi in this pack of 12 is 244.3308 in³.

Given:
12 Cylindrical can
radius of 1.25 in
height of 4.15 in

Find total volume:

Volume = π r² h  where π = 3.14
V = 3.14 * (1.25in)² * 4.15 in
V = 3.14 * 1.5625 in² * 4.15 in
V = 20.3609 in³

Volume of 20.3609 in³ is only good for one can. There are 12 cans. 

Total Volume = 20.3609 in³ x 12 cans = 244.3308 in³
4 0
3 years ago
I will mark you as brainliest if you're answer is correct​
GalinKa [24]

Answer:

perimeter = 28.13 cm

Step-by-step explanation:

Calculate the length of a line drawn from A to C.

sin 85 = b/8, b = 7.97

cos 85 = c/8, c = 0.697

AC² =7.97² + (6 + 0.697)² = 63.52 + 44.85 = 108.37

AC = 10.41

Now you have a right triangle ADC with a known hypotenuse and  one leg.

Using the Pythagorean theorem:

DC² = 10.41² - 5²

DC² = 108.37 - 25 = 83.37

DC = 9.13 cm

perimeter = 5 + 6 + 8 + 9.13 = 28.13 cm

8 0
2 years ago
The overhead reach distances of adult females are normally distributed with a mean of 197.5 cm197.5 cm and a standard deviation
fiasKO [112]

Answer:

a) 5.37% probability that an individual distance is greater than 210.9 cm

b) 75.80% probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

c) Because the underlying distribution is normal. We only have to verify the sample size if the underlying population is not normal.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 197.5, \sigma = 8.3

a. Find the probability that an individual distance is greater than 210.9 cm

This is 1 subtracted by the pvalue of Z when X = 210.9. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{210.9 - 197.5}{8.3}

Z = 1.61

Z = 1.61 has a pvalue of 0.9463.

1 - 0.9463 = 0.0537

5.37% probability that an individual distance is greater than 210.9 cm.

b. Find the probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

Now n = 15, s = \frac{8.3}{\sqrt{15}} = 2.14

This probability is 1 subtracted by the pvalue of Z when X = 196. Then

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{196 - 197.5}{2.14}

Z = -0.7

Z = -0.7 has a pvalue of 0.2420.

1 - 0.2420 = 0.7580

75.80% probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

The underlying distribution(overhead reach distances of adult females) is normal, which means that the sample size requirement(being at least 30) does not apply.

5 0
3 years ago
Frank is trying to factor y^2+6y-27 . He has determined that one factor is (y + 9). What is the other factor? A. y – 27 B. y – 6
beks73 [17]
The other factor is (y - 3).  If you multiply the two terms together, you will end up with y^2+6y-27:

(y - 3)(y + 9) \\ y^{2} +9y-3y-27 \\ y^2+6y-27
5 0
3 years ago
Read 2 more answers
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