Question

A force of 9 lb is required to hold ​35lb crate on a hill. What angle does the hill make with the​ horizontal?

Answer 1

Answer: $14.9^{\circ}$

Step-by-step explanation:

Given

Applied force is 9 lb to hold of 35 lb crate on a hill

Suppose the hill makes an angle of $\theta$ with horizontal

There will be two component of weights i.e. along and perpendicular to the hill

Only the component along the hill pulls the crate backwards

So,

$\Rightarrow 35\sin \theta=9\\\\\Rightarrow \sin\theta =\dfrac{9}{35}\\\\\Rightarrow \theta =14.89^{\circ}\approx 14.9^{\circ}$