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ra1l [238]
2 years ago
6

Solve 2 – 4<5. Graph the solution. The solution is

Mathematics
2 answers:
Arturiano [62]2 years ago
6 0

Answer:

x < 9

Step-by-step explanation:

Move the -4 over as if there was an equal sign so that x < 9

Take the arrow that looks like this "<---O" that is not filled in and put it on the number 9.

Let me know if this helps <3

SashulF [63]2 years ago
5 0

Answer:

x < 9

Step-by-step explanation:

The graphed solution starts with a open circle on the 9 number on the number line. Then there is a line that extends from the open circle all the way to the left.

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I need atleast 5 volunteers for the magic trick
Leto [7]

What magic trick??

Are you gonna do a magic??

Sorry for a lot of questions.

3 0
2 years ago
Given that A=xy find the percentage increase in A when both X and Y increase by 10%
Lelechka [254]
A=xy
If there is 10% increase in x then,
New value of x = x + 10%of x =1.1x
similarly for y
New value of y after increase= 1.1 y
New value of A after increase in x and y = 1 .1x × 1.1 y= 1.21xy
now
increase amount in A= New value of A - old value of A
=1.21xy - xy= 0.21xy
percentage increase in A= (0.21xy÷xy )× 100= 21%
7 0
3 years ago
How do you solve this one 10x^2-25=x^2
solong [7]
10x^2 - 25 = x^2
Take the square root of each side.

\sqrt{x^2} =  \sqrt{10x^2 - 25}
x = 10x - 5i




4 0
3 years ago
At the local pet store, zebra fish cost $2.00 each and neon tetras cost $2.15 each. If Ernesto bought 15 fish for a total cost o
bezimeni [28]
So first create and define your variables:
Z = amount of zebra fish
N = amount of neon tetras

Now create your equations:
2z+2.15n=31.20
z+n=15
This is your system. There are multiple methods to use but in this problem I’ll use the substitution method by simplifying the bottom equation.
2z+2.15n=31.20
z=15-n
Now I’ll plug the bottom equation into the top one.
2(15-n)+2.15n=31.20
And just solve from here.
30-2n+2.15n=31.20
0.15n=1.20
n=8
So he bout 8 neon tetras, and 15-8= 7, so he bought 7 zebra fish
6 0
3 years ago
Read 2 more answers
Lucy is using a one-sample t ‑test based on a simple random sample of size n = 22 to test the null hypothesis H 0 : μ = 16.000 c
slega [8]

Answer:

The value of test statistic is 1.338

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 16.000

Sample mean, \bar{x} = 16.218

Sample size, n = 22

Alpha, α = 0.05

Sample standard deviation, s = 0.764

First, we design the null and the alternate hypothesis

H_{0}: \mu = 16.000\text{ cm}\\H_A: \mu < 16.000\text{ cm}

We use one-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{16.218 - 16.000}{\frac{0.764}{\sqrt{22}} } = 1.338

Thus, the value of test statistic is 1.338

4 0
4 years ago
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