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3 years ago

A shop is having a sale all items are reduced work out the sale price of an item normally priced at £60

Mathematics

1 answer:

Naddik [55]3 years ago

3 0

Question:

A shop is having a sales all items are reduced by 25%. Work out the sale price of an item normally priced at £60?

Answer:

The new price is £45

Step-by-step explanation:

Given

$Sales\ price = \pounds 60$

$Rate = 25\%$

First, calculate the reduction

$Reduction = Rate * Sales\ price$

$Reduction = 25\% * \pounds 60$

$Reduction = \pounds 15$

The new price is:

$New = Sales\ price - Reduction$

$New = \pounds 60 - \pounds 15$

$New = \pounds 45$

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Prove: The difference of the reciprocals

murzikaleks [220]

Step-by-step explanation:

let two successive integers n, n+1

difference of the reciprocals:

$\frac{1}{n}-\frac{1}{n+1} \\=\frac{(n+1)-n}{(n)(n+1)}\\=\frac{1}{(n)(n+1)}\\=\frac{1}{(n)}\frac{1}{(n+1)}\\$

7 0

3 years ago

A worker's wage (w) is directly proportional to the number of hours (h) worked. If $71.25 is earned for working 5 h, how much is

marissa [1.9K]

Answer:

The amount earned is $327.75

Step-by-step explanation:

If the workwr working for 5h gets $71.25, then his working for 1 hour could be said to be x.

5h = $71.25

1h = x; cross multiplying would result in

x= $\frac{($71.25*1)}{5h}$

x= $14.25 which is the pay for 1h

Therefore for 23 h the worker would earn

23* 14.25 = $327.75

5 0

3 years ago

Find the laplace transform of f(t) = cosh kt = (e kt + e −kt)/2

iren2701 [21]

Hello there, hope I can help!

I assume you mean $L\left\{\frac{ekt+e-kt}{2}\right\}$
With that, let's begin

$\frac{ekt+e-kt}{2}=\frac{ekt}{2}+\frac{e}{2}-\frac{kt}{2} \ \textgreater \ L\left\{\frac{ekt}{2}-\frac{kt}{2}+\frac{e}{2}\right\}$

$\mathrm{Use\:the\:linearity\:property\:of\:Laplace\:Transform}$
$\mathrm{For\:functions\:}f\left(t\right),\:g\left(t\right)\mathrm{\:and\:constants\:}a,\:b$
$L\left\{a\cdot f\left(t\right)+b\cdot g\left(t\right)\right\}=a\cdot L\left\{f\left(t\right)\right\}+b\cdot L\left\{g\left(t\right)\right\}$
$\frac{ek}{2}L\left\{t\right\}+L\left\{\frac{e}{2}\right\}-\frac{k}{2}L\left\{t\right\}$

$L\left\{t\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{t\right\}=\frac{1}{s^2} \ \textgreater \ L\left\{t\right\}=\frac{1}{s^2}$

$L\left\{\frac{e}{2}\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{a\right\}=\frac{a}{s} \ \textgreater \ L\left\{\frac{e}{2}\right\}=\frac{\frac{e}{2}}{s} \ \textgreater \ \frac{e}{2s}$

$\frac{ek}{2}\cdot \frac{1}{s^2}+\frac{e}{2s}-\frac{k}{2}\cdot \frac{1}{s^2}$

$\frac{ek}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{ek\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{ek}{2s^2}$

$\frac{k}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{k\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{k}{2s^2}$

$\frac{ek}{2s^2}+\frac{e}{2s}-\frac{k}{2s^2}$

Hope this helps!

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3 years ago

What is 5 *63 in distributive property

lianna [129]

5*(60+3) You should write 63 in this way 60+3

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3 years ago

HELP me. I will rate 5 stars.

kaheart [24]

Answer:i would help but the picture is tooooo blurry

Step-by-step explanation:

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3 years ago