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yarga [219]
2 years ago
10

What is the perimeter, in feet, a rectangle whose length is twice its width and whose width is 8 feet?

Mathematics
1 answer:
anyanavicka [17]2 years ago
4 0
If the width is 8ft and the length is twice the width then multiply 8 by 2 to find your length
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2 years ago
rewrite the polynomial 2y^2+ 6y^3-11-17y^4+8y^5 in the standard form also find its degree and coefficient of y^4
OleMash [197]

Answer:

The standard form is  8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11

The degree of given polynomial is '5'

the co-efficient of  y⁴  is '-17'

Step-by-step explanation:

Given standard form 2 y²+ 6 y³-11-17 y⁴+8 y⁵

<em>The form ax² + b x + c is called the standard form of the quadratic expression of 'x'.This is second degree standard form of polynomial.</em>

<em>The form ax⁵ + b x⁴ + c x³ +d x² +ex +f  is called the standard form of the quadratic expression of 'x'.This is fifth degree standard form of polynomial</em>

now Given polynomial is  2 y²+ 6 y³-11-17 y⁴+8 y⁵

The standard form is

                                8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11

<u><em>Conclusion</em></u>:-

<em>The degree of given polynomial is '5'</em>

<em>The co-efficient of  y⁴  is '-17'</em>

<em>   </em>

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Translate and solve: 6 fewer than s is no less than −78
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Answer:

Part 1: S-6\geq -78 Part 2: S\geq-72

Step-by-step explanation:

Trust me.. it makes sense

3 0
2 years ago
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