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2 years ago

What is the perimeter, in feet, a rectangle whose length is twice its width and whose width is 8 feet?

Mathematics

1 answer:

anyanavicka [17]2 years ago

4 0

If the width is 8ft and the length is twice the width then multiply 8 by 2 to find your length

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Zina [86]

Answer: A

Step-by-step explanation:

In a function, one x value (the number in front) goes to one y value.

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3 years ago

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2 years ago

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2 years ago

Find the value of Cot(450°+theta)

Leya [2.2K]

$cot(450\° + \theta) = \frac{1}{tan(450\° + \theta)}$
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6 0

2 years ago

Help me with a. b. c. I need help

hammer [34]

Answer:

a) Perimeter = 20.5 Inches

Area is 15 Sq Inches

b) Perimeter is 61.4 Cms

Area is 210 Sq cm

c) Perimeter is 22 yards

Area is 21 Sq Yards

Step-by-step explanation:

a) Perimeter = sum of all the sides

= 8+7.5+5

=20.5

Perimeter = 20.5 Inches

Area of Triangle = $\frac{1}{2} \times height \times Base$

Base = 7.5 In

Height = 4 In

$A = \frac{1}{2} \times 4 \times 7.5$

$A = 2 \times 7.5$

$A = 15$

Hence Area is 15 Sq Inches

b) Perimeter = Sum of all the sides

P=13+23+13.4+12

P=61.4

Perimeter is 61.4 Cms

Area of trapezium = $\frac{1}{2} \times height \times (sum \ of \ parallel \ sides)$

$A= \frac{1}{2} \times 12 \times (12+23)$

$A= 6 \times 25$

$A=210$

Area is 210 Sq cm

c) Perimeter = Sum of all the sides

P = 7+4+7+4 ( as Opposite sides are equal in a parallelogram

P = 22

Perimeter is 22 yards

Area of a parallelogram = $base \times height$

$A= 7 \times 3$

$A = 21$

Area is 21 Sq Yards

3 0

3 years ago