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2 years ago

Factrise x^2 -12x+32

Mathematics

1 answer:

Klio2033 [76]2 years ago

6 0

Answer:

(x - 8) (x - 4)

Step-by-step explanation:

Hope this helps! :D

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Factor completely 8x2 − 4x − 84. 4(2x − 3)(x 7) 4(2x 3)(x − 7) 4(x − 3)(2x 7) 4(x 3)(2x − 7).

gizmo_the_mogwai [7]

The factor of the given equation $8x^{2} -4x-84$ will be $4(x+3)(2x-7)$

<h3>What will be the factor of the given equation?</h3>

Given equation is $8x^{2} -4x-84$

Now taking 2 commons from the equation

$4(2x^{2} -x-21)$

now splitting the equation we get

$4(2x^{2} +6x-7x-21)$

$4(2x(x+3)-7(x+3))$

$4(x+3)(2x-7)$

Thus the factor of the given equation $8x^{2} -4x-84$ will be

$4(x+3)(2x-7)$

To know more about Factors of quadratic equation follow

brainly.com/question/1214333

7 0

2 years ago

HELP ME LOL AND EXPLAIN HOW TO DO IT (if u can) LOL IM SO ST00PID

Blizzard [7]

Answer:

The answer is B

Language has nothing to do with finding out who the spectators support. So it is b. This is because b does talk about asking the spectators who they support.

5 0

3 years ago

Read 2 more answers

In the figure, a∥b and m∠3 = 34°.<br><br> What is the m∠7 ?<br><br> Enter your answer in the box.

solmaris [256]

Answer:

∠7 = 34°

Step-by-step explanation:

Since a and b are parallel lines then

∠3 and ∠7 are corresponding angles and congruent, so

∠7 = ∠3 = 34°

4 0

3 years ago

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :

$\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}$

$k \approx \pm 0.028$

The positive value of $k$ will result in exactly one real root is approximately 0.028.

7 0

2 years ago

To solve the inequality m/-7<(or equal to) 14 , what should be done to both sides?

Marizza181 [45]

Answer:

$\large\boxed{m\geq-98}$

Step-by-step explanation:

$\dfrac{m}{-7}\leq14\\\\-\dfrac{m}{7}\leq14\qquad\text{change the signs}\\\\\dfrac{m}{7}\geq-14\qquad\text{multiply both sides by 7}\\\\7\!\!\!\!\diagup^1\cdot\dfrac{m}{7\!\!\!\!\diagup_1}\geq(7)(-14)\\\\m\geq-98$

5 0

3 years ago

Read 2 more answers