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Vanyuwa [196]
3 years ago
15

Can anyone give me the variables

Mathematics
2 answers:
Vlad1618 [11]3 years ago
5 0

Answer:

30 miles from your home

Step-by-step explanation:

You will meet at distance d from your home.

You will drive distance d at 30 mph until you meet them for t time.

Your uncle and aunt already traveled 5 miles before you start, so when you meet them, they will have traveled d - 5 miles from the moment you start. They travel d - 5 miles in the same time t you travel d miles.

speed = distance/time

time = distance/speed

Your uncle and aunt:

t = (d - 5)/25

You:

t = d/30

The t is the same for both, so we equate the right sides of the equations above.

(d - 5)/25 = d/30

Multiply both sides by the LCD of 25 and 30 which is 150.

150 * (d - 5)/25 = 150 * d/30

6d - 30 = 5d

d = 30

Answer: 30 miles from your home

AveGali [126]3 years ago
4 0

9514 1404 393

Answer:

  the variables are the time and/or distance "you" traveled.

Step-by-step explanation:

The problem gives two relations between speed, time, and distance. The speeds are given, so you could define variables for the time and distance of travel.

Since the question asks only for the distance until the parties meet, only one variable is necessary. That variable could represent either the time or the distance to the meeting point. (It more directly answers the question if it represents the distance, but it may make the equation more difficult to write.)

In every case, distance = speed × time.

_____

Here are three ways to set up the problem.

__

Using d for distance (miles), t for time (hours) since "you" started.

  d = 5 + 25t . . . . . distance traveled by aunt and uncle

  d = 30t . . . . . . . . distance traveled by you

__

Using t for time (hours) since "you" started.

  5 +25t = 30t . . . . time until the distances traveled are the same

  for this, the answer to the question is 5+25t or 30t, as you wish

__

Using d for distance (miles) until the parties meet

  d = 5 +(d/30)(25) . . . . . aunt and uncle traveled (d/30) hours at 25 mph

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Answer: First train speed shall be 42 mi/hr

Second train speed shall be 84 mi/hr

Yes it is the valid answer, it gets annoying when almost everyone enters the wrong answer for a good laugh. Either way, hope this helps! Have a spectacular day.

Step-by-step explanation:

What is the 1st train's head start in miles?

Let +s+ = the speed of the 1st train in mi/hr

From 2PM to 4PM is 2 hrs

+d%5B1%5D+=+s%2A2+

---------------------

Let +d+ = distance the 2nd train travels until

it overtakes the 1st train

From 4PM to 6PM is 2 hrs

Start time when the 2nd train leaves

---------------------

Equation for 1st train:

(1) +d+-+2s+=+s%2A2+

Equation for 2nd train:

(2) +d+=+%28+s%2B42+%29%2A2+

--------------------

Substitute (2) into (1)

(1) +%28+s%2B42+%29%2A2+-+2s+=+s%2A2+

(1) +2s+%2B+84+-+2s+=+2s+

(1) +2s+=+84+

(1) +s+=+42+

and

+s%2B+42+=+42+%2B+42+

+s+%2B+42+=+84+

------------------

The 1st train's speed is 42 mi/hr

The 2nd train's speed is 84 mi/hr

---------------------------

check:

(2) +d+=+%28+s%2B42+%29%2A2+

(2) +d+=84%2A2+

(2) +d+=+168+

and

(1) +d+-+2s+=+s%2A2+

(1) +d+-+2%2A42+=+42%2A2+

(1) +d+=+84+%2B+84+

(1) +d+=+168+

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