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3 years ago

I need help thank you

Mathematics

2 answers:

torisob [31]3 years ago

6 0

Answer:

B. HL

Step-by-step explanation:

Serga [27]3 years ago

4 0

Answer:

C i think

Step-by-step explanation:

pls mark brainlyest

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What does a quadrilateral look like, i'll look it up but its so fun on this

nlexa [21]

A shape that has four corners and four sides like a square, rectangle, or dimond

7 0

2 years ago

At the school the ratio of boys to girls is 5:3 if there are 385 boys in the school, how many students are there altogether?

ser-zykov [4K]

Answer:

There are 616 total students

Step-by-step explanation:

boys : girls: total

5 3 5+3 = 8

There are 385 boys

385/5 = 77

Multiply each term by 77

boys : girls: total

5*77 3*77 8*77

385 539 616

There are 616 total students

6 0

2 years ago

Read 2 more answers

Jose can paint an entire house in seven hours and brandon can paint the same house in eight hours. Write an equation that can be

guajiro [1.7K]

Answer:

t/8 + t/7 = 1

Step-by-step explanation:

Given in the question that,

time require for Jose to paint the house = 7 hours

time require for Brandon to paint the house = 8 hours

Suppose t means Full house painted.

<h3>To solve the question we have to figure out how much each of them can paint in ONE hour.</h3>

7 hours----t

1 hour ---- t/7

8 hours----t

1 hour ---- t/8

<h3>Equation</h3>

t/8 + t/7 = 1 (in one hour)

(7t + 8t)/8(7) = 1

15t/56 = 1

15t = 56

t = 56/15

t = 3.73 hours

5 0

2 years ago

1. Write a survey question for which you would expect to collect numerical

Yakvenalex [24]

Answer:

How many siblings do you have?

I hope this helps you out :)

5 0

3 years ago

A teacher places n seats to form the back row of a classroom layout. Each successive row contains two fewer seats than the prece

Alex_Xolod [135]

Answer:

The number of seat when n is odd $S_n=\frac{n^2+2n+1}{4}$

The number of seat when n is even $S_n=\frac{n^2+2n}{4}$

Step-by-step explanation:

Given that, each successive row contains two fewer seats than the preceding row.

Formula:

The sum n terms of an A.P series is

$S_n=\frac{n}{2}[2a+(n-1)d]$

$=\frac{n}{2}[a+l]$

a = first term of the series.

d= common difference.

n= number of term

l= last term

$n^{th}$ term of a A.P series is

$T_n=a+(n-1)d$

n is odd:

n,n-2,n-4,........,5,3,1

Or we can write 1,3,5,.....,n-4,n-2,n

Here a= 1 and d = second term- first term = 3-1=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=1 and d=2

$n=1+(t-1)2$

⇒(t-1)2=n-1

$\Rightarrow t-1=\frac{n-1}{2}$

$\Rightarrow t = \frac{n-1}{2}+1$

$\Rightarrow t = \frac{n-1+2}{2}$

$\Rightarrow t = \frac{n+1}{2}$

Last term l= n,, the number of term $=\frac{ n+1}2$ , First term = 1

Total number of seat

$S_n=\frac{\frac{n+1}{2}}{2}[1+n}]$

$=\frac{{n+1}}{4}[1+n}]$

$=\frac{(1+n)^2}{4}$

$=\frac{n^2+2n+1}{4}$

n is even:

n,n-2,n-4,.......,4,2

Or we can write

2,4,.......,n-4,n-2,n

Here a= 2 and d = second term- first term = 4-2=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=2 and d=2

$n=2+(t-1)2$

⇒(t-1)2=n-2

$\Rightarrow t-1=\frac{n-2}{2}$

$\Rightarrow t = \frac{n-2}{2}+1$

$\Rightarrow t = \frac{n-2+2}{2}$

$\Rightarrow t = \frac{n}{2}$

Last term l= n, the number of term $=\frac n2$ , First term = 2

Total number of seat

$S_n=\frac{\frac{n}{2}}{2}[2+n}]$

$=\frac{{n}}{4}[2+n}]$

$=\frac{n(2+n)}{4}$

$=\frac{n^2+2n}{4}$

4 0

2 years ago