Well, for 4 I believe you must divide 2/4 by 100 to make it a decimal, then divide the decimal by the 5. :) Hopefully that is correct!
Answer:
nonlinear increasing
Step-by-step explanation:
Answer:
μ−2σ = 1,089.26
μ+2σ = 1,097.62
Step-by-step explanation:
The standard deviation of a sample of size 'n' and proportion 'p' is:
![\sigma=\sqrt{\frac{p*(1-p)}{n} }](https://tex.z-dn.net/?f=%5Csigma%3D%5Csqrt%7B%5Cfrac%7Bp%2A%281-p%29%7D%7Bn%7D%20%7D)
If n=1139 and p =0.96, the standard deviation is:
![\sigma=\sqrt{\frac{p*(1-p)}{n}}\\\sigma = 0.001836](https://tex.z-dn.net/?f=%5Csigma%3D%5Csqrt%7B%5Cfrac%7Bp%2A%281-p%29%7D%7Bn%7D%7D%5C%5C%5Csigma%20%3D%200.001836)
The minimum and maximum usual values are:
![\mu-2\sigma = (p-2\sigma)*n\\\mu+2\sigma = (p+2\sigma)*n](https://tex.z-dn.net/?f=%5Cmu-2%5Csigma%20%3D%20%28p-2%5Csigma%29%2An%5C%5C%5Cmu%2B2%5Csigma%20%3D%20%28p%2B2%5Csigma%29%2An)
![\mu-2\sigma = (0.96-2*0.001836)*1139\\\mu-2\sigma = 1,089.26\\\mu+2\sigma = (0.96+2*0.001836)*1139\\\mu+2\sigma = 1,097.62](https://tex.z-dn.net/?f=%5Cmu-2%5Csigma%20%3D%20%280.96-2%2A0.001836%29%2A1139%5C%5C%5Cmu-2%5Csigma%20%3D%201%2C089.26%5C%5C%5Cmu%2B2%5Csigma%20%3D%20%280.96%2B2%2A0.001836%29%2A1139%5C%5C%5Cmu%2B2%5Csigma%20%3D%201%2C097.62)
Everyone would be confused because they wouldnt know how to add. if there wasnt money then there with be no objects/food/toys/ect. unless its all free. If it all free then everyone would go crazy because they wouldnt have to calculate how much the item cost.