Three lines given -- it's a natural for the cos(theta) law. A small hint: I think the preferred way of doing it is to use the cos(theta) law twice. It will give you a definite answer.
Find G first
g = 6 yd
h = 7 yd
f = 5 yards.
g^2 = h^2 + f^2 - 2*h*f*cos(G)
6^2 = 7^2 + 5^2- 2*7*5*cos(G)
36 = 49 + 25 - 70*Cos(G)
36 = 74 - 70*cos(G)
-48 = - 70 * cos(G) Divide by -70
-38/-70 = cos(G)
0.5429 = cos(G)
cos-1(0.5429) = G
G = 57.12
Now find H
h^2 = g^2 + f^2 - 2*g*f*cos(H)
7^2 = 5^2 + 6^2 - 2*5*6*cos(H)
49 = 25 + 36 - 60cos(H)
49 =61 - 60*cos(H)
Cos(H) = -12 / - 60
Cos(H) = 0.2
H = cos-1(0.2)
H = 78.46
F can be found because every triangle has 180 degrees
F + 78.46 + 57.12 = 180
F + 135.58 = 180
F = 180 - 135.58
F = 44.41
A <<<< Answer.
Answer:
hope it helps you..,.....,..........
Answer:
30°
Step-by-step explanation:
First we take the full amount of degrees from points A to C, which is given as 125° then subtract 94°, which is the given amount from points A to D, this results in 30°
Answer:
C. The coefficient of variation is a measure of relative dispersion that expresses the standard deviation as a percentage of the mean, for any data on a ratio scale and an interval scale
Step-by-step explanation:
Th Coefficient of Variance is a measure of dispersion that can be calculated using the formula:
Where 
is the Standard Deviation
and 
is the sample mean
From the formula written above, it is shown that the Coefficient of Variation expresses the Standard Deviation as a percentage of the mean.
Coefficient of variation can be used to compare positive as well as negative data on the ratio and interval scale, it is not only used for positive data.
The Interquartile Range is not a measure of central tendency, it is a measure of dispersion.
