<u>ANSWER:</u>
If
and
then the difference of a and b is 6
<u>SOLUTION:</u>
Given,
→
----- (1)
And
→
--- (2)
We have to find difference of a and b.
Now, add (1) and (2)


Adding above two equations, we get,


substitute
value in (2)

Now, difference of a and b is a – b = 
Hence, the difference of a and b is 6.
9514 1404 393
Answer:
C) c || d by converse of corresponding angles
Step-by-step explanation:
Only corresponding angles where transversal b crosses lines c and d are shown. All answer choices involving a||b or interior angles can be eliminated from consideration.
The "corresponding angle" theorem tells you corresponding angles are congruent if the lines are parallel.
The converse of that theorem tells you the lines are parallel if the corresponding angles are congruent. Here, the angles are shown congruent, so the "converse" theorem applies.
Answer:
1/72
Step-by-step explanation:
Answer:
(1, 5)
Step-by-step explanation:
The solution to the system of equations is the point of intersection of the two lines. From inspection of the graph, the point of intersection is at (1, 5).
<u>Proof</u>
The solution to a system of equations is the point at which the two lines meet.
⇒ g(x) = f(x)
⇒ 3x + 2 = |x - 4| + 2
⇒ 3x = |x - 4|
⇒ 3x = x - 4 and 3x = -(x - 4)
⇒ 3x = x - 4
⇒ 2x = -4
⇒ x = -2
Inputting x = -2 into the 2 equations:
⇒ g(-2) = 3 · -2 + 2 = -4
⇒ f(-2) = |-2 - 4| + 2 = 8
Therefore, as the y-values are different, x = -2 is NOT a solution
⇒ 3x = -(x - 4)
⇒ 3x = 4 - x
⇒ 4x = 4
⇒ x = 1
Inputting x = 1 into the 2 equations:
⇒ g(1) = 3 · 1 + 2 = 5
⇒ f(1) = |1 - 4| + 2 = 5
Therefore, as the y-values are the same, x = 1 IS a solution
and the solution is (1, 5)
Alright, let's factor this to get the answer.
3k^2-10k+7
To find the factors, we want to think "What will add up to -10, and multiply to (+)7?"
Because the leading coefficient is 3, we know that we can take one factor of 7 and multiply it by 3.
Thus, this factors to
(3k-7)(k-1)
(if you FOIL it it should come out to be the original equation)
From this, set both of those [(3k-7) and (k-1)] equal to zero and solve
3k-7=0
3k=7
/3
k=7/3
or
k=1