<h3>
Answer: 17</h3>
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Work Shown:
a1 = 3 = first term
d = 2 = common difference (since we add 2 to each term to get the next one)
Let's compute the nth term.
an = a1 + (n-1)*d
an = 3 + (n-1)*2
an = 3 + 2n-2
an = 2n+1
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To check things so far, we can plug in something like n = 2
an = 2n+1
a2 = 2*2+1
a2 = 5
Showing that the 2nd term is 5, which matches with the sequence given to us
Let's check n = 3
an = 2n+1
a3 = 2*3+1
a3 = 7
That matches as well. I'll let you check the others.
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Plug in n = 8 to find the 8th term
an = 2n+1
a8 = 2*8+1
a8 = 17
The eighth term is 17, which is the final answer.
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You could extend out the given sequence by adding 2 each time until you reach the 8th term
3,5,7,9,11,13,15,17
Though this method is slow if you need to find say the 38th term
Answer:
2
Step-by-step explanation:
negative numbers dividing with negative have positive quotients
Answer:
7
Step-by-step explanation:

This is the sum of the first three terms of a geometric sequence, where the first term is 4 and the common ratio is ½.
We can use a formula to find the sum, or, since there's only three terms, we can find the value of each term then add up the results.
4 · (½)¹⁻¹ = 4
4 · (½)²⁻¹ = 2
4 · (½)³⁻¹ = 1
4 + 2 + 1 = 7
QUESTION:
The code for a lock consists of 5 digits (0-9). The last number cannot be 0 or 1. How many different codes are possible.
ANSWER:
Since in this particular scenario, the order of the numbers matter, we can use the Permutation Formula:–
- P(n,r) = n!/(n−r)! where n is the number of numbers in the set and r is the subset.
Since there are 10 digits to choose from, we can assume that n = 10.
Similarly, since there are 5 numbers that need to be chosen out of the ten, we can assume that r = 5.
Now, plug these values into the formula and solve:
= 10!(10−5)!
= 10!5!
= 10⋅9⋅8⋅7⋅6
= 30240.
First: Find out how many of Jolie's balls are blue.
300 * 35% = 300 * 0.35 = 105 blue balls.
Second: Find the difference between the total number of balls and the blue balls to find out how many green balls Jolie has.
300 - 105 = 195 green balls.