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timama [110]
3 years ago
13

The line segment formed by joining points A (-1,y) B (0,0), and the line segment joined by forming points C (6,3) D (8,9) share

the same slope. What is the value of y?
Hint - The lines are parallel!

please answered
Mathematics
1 answer:
Airida [17]3 years ago
8 0

Answer:

<h3>-3</h3>

Step-by-step explanation:

For two parallel lines. their slope are equal

Find the slope of each of the lines

For line A;

m = 0 -y/0+1

mA = -y/1

For line B;

mB = 9 - 3/8 - 6

mB = 6/2

mB = 3

since their slope are equal hence mA = mB

-y/1 = 3

-y = 3

y = -3

Hence the value of y is -3

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3p - 5 = 19<br> Answer when solved??
lianna [129]

Answer: P=8

Step-by-step explanation:

3p-5=19

U turn -5 to +5

Then u add 5 to both sides, -5 and 19

3p-5=19

+5=+5

-5 and +5 cancel each other out so know it’s

3p=24

Because 19 plus 5 is 24

Now u have to get the variable by itself by dividing 3 on both sides of the equal sign 3p and 24

3 and 3 cancel each other out so now you only have p=24 but then 24 divided 3 is 8

3 0
3 years ago
Find the directional derivative of f(x,y,z)=z3−x2yf(x,y,z)=z3−x2y at the point (−5,5,2)(−5,5,2) in the direction of the vector v
olga_2 [115]

We are given

f=z^3 -x^2y

Firstly, we can find gradient

so, we will find partial derivatives

f_x=0 -2xy

f_x=-2xy

f_y=0 -x^2

f_y=-x^2

f_z=3z^2

now, we can plug point (-5,5,2)

f_x=-2*-5*5=50

f_y=-(-5)^2=-25

f_z=3(2)^2=12

so, gradient will be

gradf=(50,-25,12)

now, we are given that

it is in direction of v=⟨−3,2,−4⟩

so, we will find it's unit vector

|v|=\sqrt{(-3)^2+(2)^2+(-4)^2}

|v|=\sqrt{29}

now, we can find unit vector

v'=(\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })

now, we can find dot product to find direction of the vector

dir=(gradf) \cdot (v')

now, we can plug values

dir=(50,-25,12) \cdot (\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })

dir=(-\frac{150}{\sqrt{29} } - \frac{50}{\sqrt{29} } - \frac{48}{\sqrt{29} })

dir=-\frac{248\sqrt{29}}{29}.............Answer



7 0
3 years ago
Read 2 more answers
Linear Relationships Study Guide 1.) Select all the equations for which (-6, -1) is a solution. Show your work to prove that eac
TiliK225 [7]

we have point (-6, - 1)

Now we will put these points in each equation,

y = 4x +23

put x = -6 and y = -1

-1 = 4 (-6) +23

-1 = -24 + 23

-1 = -1

LHS = RHS, so this equation has (-6 , -1) as solution.

y = 6x

put x = -6 and y = -1

-1 = 6 (-6)

-1 not= -36

LHS is not equal RHS, so (-6 , -1) is not a solution for that equation,

y = 3x - 5

put x = -6 and y = -1

-1 = 3 (-6) - 5

-1 = -18 - 5

-1 not= -23

LHS is not equal RHS, so (-6 , -1) is not a solution for that equation,

y= 1/6 x

put x = -6 and y = -1

-1 = -6/6

-1 = -1

LHS = RHS, so (-6 , -1) is a solution for that equation,

6 0
1 year ago
What is 79.35 divided by 5
liraira [26]
79.35 divided by 5 equals: <u><em>15.87</em></u>
<em>~~~~~~~~~~~~~~~~~~~~~~~~~~~</em>
To check:
    243
    15.87
<span><u>  x  5.00</u>
</span>     0000
<u>    0000</u>
 79.35
<em>~~~~~~~~~~~~~~~~~~~~~~~~~~~~</em>
Hope this helped! :)
<span><em>Any more questions, please ask! :)</em></span>


5 0
3 years ago
write an equation in slop-intercept form for a line that is perpendicular to the line y= -5x-3 and has a y-intercept of 6.
jenyasd209 [6]

Answer:

The equation of the line would be y = 1/5x + 6

Step-by-step explanation:

First, to find the slope of a perpendicular line, you need to find the opposite and reciprocal of the original slope. Since the original is -5, we first change the sign (which makes it just 5). Now we take that 5 and flip it to get 1/5.

Now that we have the slope as 1/5, we can use that and the intercept in slope-intercept form to get the equation.

y = mx + b

y = 1/5x + 6

6 0
2 years ago
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