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maxonik [38]
3 years ago
15

Abigail orders a book and

Mathematics
1 answer:
kolezko [41]3 years ago
4 0

Answer:

$17.65

Step-by-step explanation:

First you have to subtract $7.65 from the total cost, $42.95.

Now, you have $35.30. Since she bought 2 DVD's, you have to divid $35.30 by 2.

Your answer is now $17.65, meaning that each DVD cost $17.65.

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Investors buy a studio apartment for $180,000. Of this​ amount, they have a down payment of $18,000. Their down payment is what
vovangra [49]

Answer:

$180,000 is 10% $9,000 is 5%

Step-by-step explanation:

To solve for this, you would set up a ratio and cross-multiply.

$18,000/$180,000 = x%/100%

(18,000)(100) = 180,000x

1,800,000 = 180,000x

10 = x

9,000/180,000 = x/100

900,000 = 180,000x

5 = x

OR

$18,000 ÷ 2 = $9,000

10% ÷ 2 = 5%

8 0
3 years ago
Perhatikan pola bilangan berikut:2,-6,18,-54,162,...​
andrezito [222]

Answer:

no comprehendo

Step-by-step explanation:

8 0
3 years ago
How to solve 36x+3(34x+9)
Softa [21]

Answer: 138x + 27

Step-by-step explanation:

First you distribute the 3, creating 102x +27.

Then you combine like terms, creating 138x + 27

You can't do anything else so that's your answer.

7 0
3 years ago
Hii please help i’ll give brainliest!!
Alja [10]

Answer:

It is Acceleration have a good day!

4 0
3 years ago
Read 2 more answers
I need this problem worked out. I already know the answer just not the work.
larisa [96]

Answer

n = 30

Explanation

To solve for n, you have to isolate it by 'getting rid' of the 18, 2, and negative sign.

You 'remove' these numbers in backward PEMDAS.

So to 'remove' the 18, you subtract both sides by 18.

3-18 = -15

-n/2+18-18 = -n/2

So now you are left with -15 = -n/2.

To 'get rid' of the 2, you multiply each side by 2.

-15×2 = -30

-n/2×2 = -n

And now you have -30 = -n.

To 'get rid' of the negative sign, you multiply both sides by -1.

-30×-1 = 30

-n×-1 = n

So you get 30 = n or n = 30.

If you still have questions I'll answer them in the comments (under this question).

6 0
3 years ago
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