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Alchen [17]
3 years ago
7

2. Sandy made several investments. She bought 1000 shares of a company’s stock for $8.60/share, she bought a bond with a face va

lue of $2500 and a coupon rate of 7%, and she invested $5000 into a fund that is expected to grow by 3.5% per year.
(a) Sandy pays a broker a commission of $14 to buy and sell stock. After one year, Sandy sold all her shares, when they were worth $9.15/share. What was her net gain or loss? Show your work.
Mathematics
1 answer:
vampirchik [111]3 years ago
6 0
The stock price per share was $8.60
Number of shares bought 1000
Total price for the shares:
(Cost per share)*(Number of shares)
=8.60*1000
=$8600

The stock price after 1 year $9.15
Total number of shares is 1000
Current price=(current share price)*(number of shares)
9.15*1000
=$9150
current value=(Current price)-(buying price)
=9150-8600
=$550

Net Profit=(Current value)-(Expenses)
=550-14
=$536
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Write <br> (−5x)(−5x)(−5x)(−5x)<br> as a power.
Yuliya22 [10]

Answer:

(-5x)^4

Step-by-step explanation:

3 0
3 years ago
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5x – (13 – x) &gt;_9x – 7
ad-work [718]

Answer:

x<_2

Step-by-step explanation:

first off solve this like a regular equation the >_ dosent matter till later

so basically first multiply - by 13 and -x so you get -13 and x (multiplying two negatives = a positive)

so its 5x-13+x>_9x-7

add 5x and x to get 6x-13 on one side

then you get 6x-13>_9x-7 then subtract -9x from both sides

so its now -3x-13>_-7 add 13 so you get -3x>_6

then divide both sides by -3 (when you divide an equation with a >< or <_ >_ by a negative number that sign switches) so it will now be x<_2

that your final answer hope this helps :)

6 0
3 years ago
g A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of pa
adoni [48]

Complete Question

A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?

Answer:

The value required is  \sigma =  0.0133

Step-by-step explanation:

From the question we are told that

   The upper specification is  USL  =  1.68 \ mm

    The lower specification is  LSL  = 1.52  \  mm

     The sample mean is  \mu =  1.6 \  mm

     The standard deviation is  \sigma =  0.03 \ mm

Generally the capability index in mathematically represented as

             Cpk  =  min[ \frac{USL -  \mu }{ 3 *  \sigma }  ,  \frac{\mu - LSL }{ 3 *  \sigma } ]

Now what min means is that the value of  CPk is the minimum between the value is the bracket

          substituting value given in the question

           Cpk  =  min[ \frac{1.68 -  1.6 }{ 3 *  0.03 }  ,  \frac{1.60 -  1.52 }{ 3 *  0.03} ]

=>      Cpk  =  min[ 0.88 , 0.88  ]

So

         Cpk  = 0.88

Now from the question we are asked to evaluated the value of  standard deviation that will produce a  capability index of 2

Now let assuming that

         \frac{\mu - LSL  }{ 3 *  \sigma } =  2

So

         \frac{ 1.60 -  1.52  }{ 3 *  \sigma } =  2

=>    0.08 = 6 \sigma

=>     \sigma =  0.0133

So

        \frac{ 1.68  - 1.60 }{ 3 *  0.0133 }

=>      2

Hence

      Cpk  =  min[ 2, 2 ]

So

    Cpk  = 2

So    \sigma =  0.0133 is  the value of standard deviation required

3 0
3 years ago
The speeds (in miles per hour) of motorists ticketed during one day on a five-mile stretch of highway are
Inga [223]

Answer:

19

Step-by-step explanation:

Range is solved by subtracting the lowest and highest numbers which int his case is 70 and 89 so that make 19

8 0
3 years ago
Solve. x /5 + 3 = 2 A) -5 B) 25 C) 5 D) - 1/5 <br><br> help me
Ilia_Sergeevich [38]
X/5 + 3 = 2
x+15=10
x=-5
Ans : A
8 0
2 years ago
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