- 4 1/5 = -21/5 = -42/10
-13 1/10 = -131/10
-42/10 - -131/10=
-42/10 + 131/10 = 89/10 = 8 9/10
answer is A
Ten and seventy-three hundredths
Answer:
Step-by-step explanation:
Let number of hours be x
<u>Lakeshore paddle cost:</u>
<u>Lake paddle cost:</u>
<u>Required inequality:</u>
- 10x + 4 < 12x
- 12x - 10x > 4
- 2x > 4
- x > 2
Lakeshore paddle costs less when time of rent is greater than 2 hours
The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.
For this case we must represent the following expression algebraically:
"eight more than the product of a number and two"
Let "x" be the variable that represents the unknown number
We have to:
the product of a number and two is represented as: 
Then, the full expression will be:

Thus, we use multiplication and addition.
ANswer:
Option C