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Alona [7]
3 years ago
8

A dime has the same value as 10 pennies. Marley brought 290 pennies to the bank. How many dimes did Marley get?

Mathematics
2 answers:
Free_Kalibri [48]3 years ago
6 0
I found the awnser by doing 10x10x2 witch equals 200. Then i know that 10x9 equals 90 so, you would get 29 dimes.
Aleonysh [2.5K]3 years ago
5 0
29. To solve all that you had to do was divide 290 by ten. This is because a group of ten pennies is equal to one dime.
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Find the distance between the two points rounding to the nearest tenth (if necessary). (2,−3) and (0,−8)
saveliy_v [14]

Answer:

square root of 29

Step-by-step explanation:

use the distance formula and then plug the numbers in, i got the sqrt(29) after i did that

6 0
3 years ago
Four more than twice a number is less than negative twelve. Find all numbers that make this statement true.
andreev551 [17]

Answer:

x<-8

Step-by-step explanation:

four more than twice a number = 4+2X

is less than negative twelve = <-12

4+2X<-12

(4-4)+2X< -12-4

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You estimated the average rental cost of a 2 bedroom apartment in Denton. A random sample of 16 apartments was taken. The sample
Zigmanuir [339]

Answer:

The new sample size required in order to have the same confidence 95% and reduce the margin of erro to $60 is:

n=28

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma=160)  

And the distribution for \bar X is:

\bar X \sim N(\mu, \frac{160}{\sqrt{n}})  

We know that the margin of error for a confidence interval is given by:  

Me=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)  

The next step would be find the value of \z_{\alpha/2}, \alpha=1-0.95=0.05 and \alpha/2=0.025  

Using the normal standard table, excel or a calculator we see that:  

z_{\alpha/2}=\pm 1.96  

If we solve for n from formula (1) we got:  

\sqrt{n}=\frac{z_{\alpha/2} \sigma}{Me}  

n=(\frac{z_{\alpha/2} \sigma}{Me})^2  

And we have everything to replace into the formula:  

n=(\frac{1.96(160)}{78.4})^2 =16  

And this value agrees with the sample size given.

For the case of the problem we ar einterested on Me= $60, and we need to find the new sample size required to mantain the confidence level at 95%. We know that n is given by this formula:

n=(\frac{z_{\alpha/2} \sigma}{Me})^2  

And now we can replace the new value of Me and see what we got, like this:

n=(\frac{1.96*160}{60})^2 =27.32

And if we round up the answer we see that the value of n to ensure the margin of error required Me=\pm 60 $ is n=28.    

5 0
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QveST [7]

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