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baherus [9]
3 years ago
15

Sabendo que 12 é raíz de p(x)=x²–mx+6 determine o valor de m A)25 B)2 C)14 D)12,5 E)7,5

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
6 0

Answer:

b

Step-by-step explanation:

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Find rates of change until you find a constant.

dy/dx=1,2,3,4,5,6

d2y/dx2=1,1,1,1,1  

So the acceleration, d2y/d2x, is constant.  This means that this is a quadratic sequence of the form a(n)=an^2+bn+c.  So we can set up a system of equations to solve for the values of a,b, and c.  Using the first three points, (1,1), (2,2), and (3,4) we have:

9a+3b+c=4, 4a+2b+c=2, and a+b+c=1  getting the differences...

5a+b=2 and 3a+b=1  and getting this difference...

2a=1, so a=1/2 making 5a+b=2 become:

2.5+b=2, so b=-1/2, making a+b+c=1 become:

1/2-1/2+c=1, so c=1  so the rule is:

a(n)=0.5x^2-0.5x+1  or if you prefer to not have decimals

a(n)=(x^2-x+2)/2
6 0
3 years ago
Read 2 more answers
The graph shows the percent y, of an initial dose of medicine remaining in a patient’s blood stream after X hours. Which functio
user100 [1]

Answer:

An exponential

Step-by-step explanation:

The second one is ratio

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A slice is made parallel to the base of a square pyramid.
Ivanshal [37]

Answer:

a) Triangle.

b) Triangle.

c) The area is 110 cm.

Step-by-step explanation:

The shape is given because it is a cross section of a Pyramid which we can see shaded in grey.

The area is given by the base times hight devided by 2. So 10cm * 22cm/2= 110cm.

Hope this helped ;)

6 0
3 years ago
A rather flimsy spherical balloon is designed to pop at the instant its radius has reached 3 centimeters. Assuming the balloon i
Anni [7]

Answer:

The radius is growing at the rate of 0.09 centimeter per second at the instant it pops.            

Step-by-step explanation:

We are given the following information in the question:

A spherical balloon is designed to pop at the instant its radius has reached 3 centimeters.

The balloon is filled with helium at a rate of 10 cubic centimeters per second .

\displaystyle\frac{dV}{dt} = 10~cm^3/sec.

We have to find fast the radius is growing at the instant it pops.

Volume of spherical balloons =

\displaystyle\frac{4}{3}\pi r^3

Differentiating, we get,

\displaystyle\frac{dV}{dt} = \frac{4}{3}\pi 3r^2 \displaystyle\frac{dr}{dt} = 4\pi r^2 \displaystyle\frac{dr}{dt}

Putting the values, we get,

10 = 4\times 3.14\times (3)^2\times \displaystyle\frac{dr}{dt}\\\\\frac{dr}{dt} = \frac{10}{4\times 3.14\times (3)^2} = 0.0884 \approx 0.09\\\\\frac{dr}{dt} = 0.09\text{ centimeter per second}

The radius is growing at the rate of 0.09 centimeter per second at the instant it pops.

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Who wants to be my friend? :)
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Answer:

I want to be your best friend

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